rez’bali, shlitsali va shponkali birikmalar
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Scroll down 👇![amaliy mashg’ulot №10 rez’bali, shlitsali va shponkali birikmalarni yig’ish. rez’bali birikmalarni hisoblashga oid masalalar yechish. 1. berilgan klemmali brikmadagi uglerodli po`latdan tayyorlangan boltlarning diametrlari aniqlansin (1 – rasm). f=1 kn , l=500 mm, f=0,2, dv=25 mm, masalaning yechilishi: birikmaning ishlashini ta`minlash uchun quyidagi shart bajarilishi kerak, ya`ni fc ·f · dv=fl; bundan fc =- klemma boltlarini sirib tortuvchi kuch; 1 – rasm fc == boltlar uchun cho`zilishdagi ruxsat etilgan kuchlanishni aniqlaymiz: [n]=2,0; [σch]= σoq/[n]=230/2=115mpa. boltning diametrini aniqlaymiz: σch=4 ·1,3 ·k ·fc/(zπd12) ≤[σch] bundan: 25 – jadvaldan, (ilovada) m 36, r=4mm bo`lgan boltni qabul qildik. 2. parmin mixli birikmalarni hisoblashga oid masallar yechish mix parchinli birikmalar ikki yoki undan ortiq listlarni yoki detallarni, maydalanmaydigan konstruktsiyalarni mixparchin yordamida biriktirish (parchinlash) uchun ishlatiladi. рarchin mix –dumaloq sterjen, kerakli formada shakllantirilgan kallakka ega bo`ladi. agar sterjenning bir uchidan ozginasi qirqib olinsa va uning bir uchi parchinlanib ma`lum shakldagi kallakka aylantirilsa parchin mix hosil bo`ladi. …](/media/previews/pages/preview_MPFu8z3.webp "rez’bali, shlitsali va shponkali birikmalar - Page 1")
![2δ==10 mm. st 2 markali po`latdan tayyorlangan yarim aylanasimon kallakli parchin mixni tanlab olamiz. chok elementlari o`lchamlari : chok qadami t = ==40 mm. uzun metall parchasini chetidan parchin mix o`qigacha bo`lgan masofa. e=1,65d==16,5 mm (parmalangan teshik uchun) e = 17 mm deb qabul qilamiz. parchin mix qatorlari orasidagi masofa a=0,6t==24 mm; a=25 mm deb qabul qilamiz. 4. zarur bo`lgan parchin mix sonini aniqlaymiz: kesimning mustahkamlik shartiga ko`ra z===3.64 bu erda i=1(topshiriq sharti bo`yicha); [τ]=140 mpa st 2 markali po`lat mix parchin uchun i = bitta chokning tekislikdagi kesim soni. egilishga mustahkamlik shartiga ko`ra z ===2.86 bu erda [σ]=280 mpa st 2 markali po`lat parchin mix uchun. z = 4 deb qabul qilamiz. 5. parchin mixli chokning konstruktsiyasini ishlab chiqamiz. uzun metall parchasini, parchin mix soniga ko`ra kengligini butunlay aniqlaymiz. b=2t==80 mm. chok parametrlari t, e, a hisoblangan qiymatlarini qabul qilamiz. 6. parchin mixli chokni mustahkamlikka tekshiramiz: i-i kesimda uzun …](/media/previews/pages/preview_Sei28JE.webp "rez’bali, shlitsali va shponkali birikmalar - Page 2")
![chok=30 mm – burchakli chok; b) gorizontal kuch ta`sirida moment ta`siridagi kuchlanish: t=fr ·l h·mm chokdagi umumiy kuchlanish: 4. shponkali va shlitsali birikmalarni hisoblashga oid masalalar yechish. dv=32mm bo`lgan valga eni b=50mm bo`lgan shkiv turli shakldagi shponkalar va shlitsalar vositasida biriktirilib, uzatilishi mumkin bo`lgan burovchi momentning eng katta qiymati aniqlansin. [σez] =60 mpa. masalaning yechilishi: a) prizmatik shponka o`rnatilganda. valning diametriga qarab prizmatik shponka tanlanadi (26 – jadval, ilovada): d=32 mm bo`lganda b×hsh, t1=4,0 shponkaning uzunligi l=40 mm qilib olamiz. b) segmentsimon shponka o`rnatilganda. valning diametriga qarab sigmentsimon shponka tanlanadi (27 –jadval, ilovada): d=32 mm bo`lganda b×h×d=8 ×11 ×28, t1=8 v) yengil seriali to`rtburchak profilli shlitsaga o`rnatilganda: d=36mm; d=32mm; z=8; h=0,5·(36-32)-2·0,4=1,2mm; l=50mm; do`r=0,5·(36·32)=37mm t=60·0,5·8·1,2·34·50=489,6 n·m 5. uzatma va yuritmalarni kinematikasini hisoblashga doir masalalar yechish 4 - rasm. zanjirli konveyer yuritmasining sxemasi. 1 - elektrodvigatel, 2 - tasmali uzatma, 3 - reduktor, 4 - zanjirli uzatma, 5 - baraban. mashinaning ish …](/media/previews/pages/preview_fXqMnM0.webp "rez’bali, shlitsali va shponkali birikmalar - Page 3")
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amaliy mashg’ulot №10 rez’bali, shlitsali va shponkali birikmalarni yig’ish. rez’bali birikmalarni hisoblashga oid masalalar yechish. 1. berilgan klemmali brikmadagi uglerodli po`latdan tayyorlangan boltlarning diametrlari aniqlansin (1 – rasm). f=1 kn , l=500 mm, f=0,2, dv=25 mm, masalaning yechilishi: birikmaning ishlashini ta`minlash uchun quyidagi shart bajarilishi kerak, ya`ni fc ·f · dv=fl; bundan fc =- klemma boltlarini sirib tortuvchi kuch; 1 – rasm fc == boltlar uchun cho`zilishdagi ruxsat etilgan kuchlanishni aniqlaymiz: [n]=2,0; [σch]= σoq/[n]=230/2=115mpa. boltning diametrini aniqlaymiz: σch=4 ·1,3 ·k ·fc/(zπd12) ≤[σch] bundan: 25 – jadvaldan, (ilovada) m 36, r=4mm bo`lgan boltni qabul qildik. 2. parmin mixli birikmalarni hisoblashga oid masallar yechish mix parchinli birikmala...
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