logarifmik tenglamalar

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1486960622_65568.ppt b x a a log log = b x a = log ) 1 ( log ) 3 2 ( log 3 3 + = + x x 1 ) 3 3 ( log 2 = + - x x x 1 5 log 6 log 5 = - x x 5 lg ) 3 2 lg( x x x x - = + + yechish: ketma-ket teng kuchli tenglamalar bilan almashtirib, topamiz: 303;232 2lg 5 10 lg)32lg( 5lg10lg)32lg(    xxx x x xx x x x x xxx javob: x=-3 ) (log log b x b x a a £ ³ ) log (log log log b x b x a a a a £ ³ aylanma jismlar yoki logarifmik tenglama ma`lum almashtirishlardan keyin ko`rinishga keltiriladi. (1) dan x=b va (2) dan x=ab yechimni topamiz. (1) (2) yechish: berilgan tenglama x ning x2+5x+2=23 tenglik bajarila-digan qiymatlardagina …

lasi ham tenglamani qanoatlantiradi. logarifmik tengsizlik lozim bo`lgan almashtirishlar bajarilgandan keyin yoki ko`rinishiga keladi. yechish: tengsizlikning mavjudlik sohasi x+2>0, yechimi esa x+2<10 bo`ladi. tengsizlik yechimini topish uchun tengsizliklar sistemasiga ega bo`lamiz, uni yechib ni yoki ni hosil qilamiz

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"logarifmik tenglamalar" haqida

1486960622_65568.ppt b x a a log log = b x a = log ) 1 ( log ) 3 2 ( log 3 3 + = + x x 1 ) 3 3 ( log 2 = + - x x x 1 5 log 6 log 5 = - x x 5 lg ) 3 2 lg( x x x x - = + + yechish: ketma-ket teng kuchli tenglamalar bilan almashtirib, topamiz: 303;232 2lg 5 10 lg)32lg( 5lg10lg)32lg(    xxx x x xx x x x x xxx javob: x=-3 ) (log log b x b x a a £ ³ ) log (log log log b x b x a a a a £ ³ …

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