matematika darslarida didaktik o’yinli texnologiyalardan foydalanish

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1426220425_60585.ppt 17 289 = . 3 , 10 139 5 = - a bunda a = 289 196 = + - 441 169 361 7 1 ; 80 7 = + x bunda x 49 16 81 25 va 125 64 × 112 343 252 - + 9 4 87 × = 81 16 6 × = 9 : 81 36 = 4 64 3 × = 25 121 16 × = 16 144 56 × = 64 49 55 × = 36 169 48 × = 49 : 196 78 = 169 625 54 + = 121 529 17 + = 16 225 49 × = 4 256 2 × = 16 289 32 × = 9 324 64 × = 196 361 38 + = 256 400 33 - = 25 484 4 - = 121 576 34 + = 81 484 35 + = 144 729 31 …

a beriladigan savollar 1. a sonining arifmetik kvadrat ildizi deb nimaga aytiladi? 2. quyidagi tenglik to’g’rimi: nima uchun? 3. ifodaning qiymatini toping: 4. bo’linmadan ildiz chiqaring: 5. hisoblang: ii-guruhga beriladigan savollar 1. a sonining kvadrat ildizi qanday topiladi? 2. ifodaning qiymatini toping: 3. taqqoslang: 4. ko’paytmadan ildiz chiqaring: 5. hisoblang: (15 daqiqa) (5 daqiqa) bu bosqichda har bir guruhga bir xil test savollari beriladi. bunda guruhlar belgilangan 6 minut ichida testni to’g’ri va aniq yechishlari talab etiladi. so’ngra har bir guruh javoblarni asoslab berishlari kerak bo’ladi. test. hisoblang: a) 16; b) 1,6; c) 0,16. hisoblang: a) 2,8; b) 28; c) 0,28. hisoblang: a) 21; b) c) 4. a ning qiymatini toping: a) a=3; b) a=0; c) a=-3 5. o’sish tartibida joylashtiring: a) a<b<c; b) c<a<b; c) b<a<c. savollar: 1 2 3 4 5 javoblar: a a c c b (10 daqiqa) krossvort savolnomasi: 1) o’zgaruvchiga ega bo’lgan tenglik nima deb …

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1426220425_60585.ppt 17 289 = . 3 , 10 139 5 = - a bunda a = 289 196 = + - 441 169 361 7 1 ; 80 7 = + x bunda x 49 16 81 25 va 125 64 × 112 343 252 - + 9 4 87 × = 81 16 6 × = 9 : 81 36 = 4 64 3 × = 25 121 16 × = 16 144 56 × = 64 49 55 × = 36 169 48 × = 49 : 196 78 = 169 625 54 + = 121 529 17 + = 16 225 49 × = 4 256 2 × = 16 289 32 × = 9 324 64 …

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