алгебра ва анализ масалаларини тақрибий ечиш

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1576308916.doc aa а = ,//,a,/ , aaaa a-aaa аaaaa ddddd d£d=d»d£=dd= 111 ()()() ,max, nnn iyii cg iii iii fcfcfx yxxx xxx î === ¶¶¶ d=dd=d»d ¶¶¶ ååå 11 1ln()ln() max, nn yyii cg ii ii fcfx xx yxx d î == ¶¶ =d=d»d ¶¶ åå a a a a - a = а a-a d a a a d³d a / aaa d =d a aa » / aaa d =d a a d d ³ // aa aaaa dd =d£=d /, aaaa aa dd =dd= ,(1) aa aaaa d =±d=± 31,732050..., a=3,1,7321 a »= 0,0001,0,00006. aa d d== aa 3 a = 1,73 a = 1,74 a = 3.14159... a p == 00010 . 0 3.1416 a = 0.000010.0001/20.00005 aa -»£= a a , ,/,/. aaaa aaaaaaa ddd d=-£d=d£=d ò = = a b dx x f f j a ) ( ) ( ) ( f j …

.08540504 3 -0.08540504 0.11025274 -0.07617298 4 -0.07617298 0.00923206 -0.07695489 5 -0.07695489 0.00078191 -0.07688878 бошланғич шарт x=?3 1 -2.34509333 5.34509333 05097218 2 05097218 3.39606552 -0.25239583 3 -0.25239583 30336802 -0.06118307 4 -0.06118307 0.19121276 -0.07821884 5 -0.07821884 0.01703577 -0.07678186 6 -0.07678186 0.00143698 -0.07690341 7 -0.07690341 0.00012155 -0.07689313 кўриниб турибдики, барча ҳолларда ҳам биз илдиз ни хатолик билан топдик. изоҳ. тенглама учун энг содда усул-бу кесмани тенг иккига бўлиш усулидир. бу усулнинг ғояси қуйидагича: кетма-кетлик қуйидагича тузилади: равшанки, аниқ ечим билан тақрибий ечим орасидаги хатолик қуйидагича: усулнинг дастурини келтирамиз: program ikkigabolish; var a,b,x,eps,e,ra,rx,y:real;k:integer; function f(x:real):real; begin f:=x-cos(x);end; function sign(x:real):integer; begin sign:=0; if x<0.0 then sign:=-1 else sign:=1;end; begin write('a,b,eps=?'); readln(a,b,eps);e:=b-a; ra:=f(a);x:=a; repeat k:=k+1;e:=e/2;rx:=f(x);y:=x+sign(ra*rx)*e;x:=y; writeln('k,x,e=',k:2,' ',x:8:4,' ',e:8:4); until e<eps; end. a,b,eps=?0 1 0.0001 k,x,e= 1 0.5000 0.5000 k,x,e= 2 0.7500 0.2500 k,x,e= 3 0.6250 0.1250 k,x,e= 4 0.6875 0.0625 k,x,e= 5 0.7188 0.0313 k,x,e= 6 0.7344 0.0156 k,x,e= 7 0.7422 0.0078 k,x,e= 8 0.7383 0.0039 …

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О "алгебра ва анализ масалаларини тақрибий ечиш"

1576308916.doc aa а = ,//,a,/ , aaaa a-aaa аaaaa ddddd d£d=d»d£=dd= 111 ()()() ,max, nnn iyii cg iii iii fcfcfx yxxx xxx î === ¶¶¶ d=dd=d»d ¶¶¶ ååå 11 1ln()ln() max, nn yyii cg ii ii fcfx xx yxx d î == ¶¶ =d=d»d ¶¶ åå a a a a - a = а a-a d a a a d³d a / aaa d =d a aa » / aaa d =d a a d d ³ // aa aaaa dd =d£=d /, aaaa aa dd =dd= ,(1) aa aaaa d =±d=± 31,732050..., a=3,1,7321 a »= 0,0001,0,00006. aa d d== aa 3 a = 1,73 a = 1,74 a = 3.14159... a p == 00010 . 0 3.1416 a = …

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