bellashuv_uz_-_9-sinf-matematika-2020

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9-sinf matematika 1-bilet 1. hisoblang: (1 ( ) +1)* 2. (a+(a-2))*2=p=32 2a-2=16 2a=18 a=9 a-2=7 javob :7sm, 9sm 3. soddalashtiring: tg(-α)ctg(-α)+cos 2 (-α)+sin 2 α tg(-α)ctg(-α)+cos 2 (-α)+sin 2 α= (-tgα)(-ctgα)+ cos 2 α + sin 2 α=1+1=2 4.romb barcha tomonlari teng bo’lgan parallelogramdir. uning dioganallari o’zaro perpendikular kesishadi. 5. a:b=4:3 a+a+b=p=66 , bundan 4x+4x+3x=11x=66 x=6 a=4x=4*6=24 b=3x=3*6=18 javob:24sm, 24sm, 18sm. 2-bilet 1. hisoblang: - - = 2. ( ) )=1 3. agar sinα+cosα= bo‘lsa, sin 3 α+cos 3 α ni hisoblang sin 3 α+cos 3 α=( sinα+cosα)*((sinα+cosα = ( sinα+cosα)* *((sinα+cosα (sinα+cosα = ( ) 4.bir burchagi to’g’ri(9 ) bo’lga uchburchak to’g’ri burchakli uchburchak deyi- ladi. uning katta tomoni tomoni gipotenuza, qolgan tomonlari esa katetlar deb ata- ladi. to’g’ri burchakli uchburchak gipotenuzasiga tushirilgan balandlik formulasi: 5. 2*(a+(a+11))=p=58sm; 2a+11=29; 2a=18; a=9; a+11=20 javob:9sm,20sm 3-bilet 01. soddalashtiring: 4+5√ + √ √ √ 5√ + √ √ √ (√ √ ) √ …

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s2sin5   = 3; 5sinx-2cox=9cosx+6sinx; sinx=-11cosx; ctgx= 4.doira bo’laklari:1.sektor------ 2.segmenti---- 5. katetlar=a; a√ gipotenuza=2a=40 javob=40sm 6-bilet 1. javob=5*b 0,5 *(b+2) 2. y=3x 2 va y=x+2 funksiyalar grafiklarini kesishish nuqtalarining koordinatalarini toping. 3x 2 =x+2 3x 2 -x-2=0 x=1;- - 4. ikkita uchburchakning burchaklari teng a tomonlari nisbati mos ravishda teng bo’lsa, bu uchburchaklar o’xshash uchburchaklar deyiladi. uchburchaklar o’xshashligining 2-alomati-tbt(tomon-burchak-tomon) alomatidir. 5. s= , bundan p=2*(18+12)=60 javob:60sm 7-bilet 1. 3 9 +3 8 +3 7 +2•3 6 ifodaning qiymatini 41 ga qoldiqsiz bo‘linishini isbotlang. 39+38+37 +2• 2. │8-4x│< 32 tengsizlikning nechta butun yechimlari bor? -32 2)4x , bundan -6 3. cosa= 1) sina= √ √ √ 2) tga= 4. kosinuslar teoremasi: a 2 =b 2 +c 2 -2bc*cosa yoki cosa= 5. – | | √ √ √ 8-bilet 1.2√ √ √ (√ ) (√ )(√ ) √ √ = 2. 12≤6-3x<18; 1)3x 2)3x -4 3. soddalashtiring: sin 4 x-cos 4 …

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2 a.s= 1) x2-5x= 5x-x2 2x2=10x x=0 x=5 2) x2-5x= x2-5x x javob:x=0;5 4.qarama-qarshi tomonlari teng va parallel bo’lgan to’rtburcha to’g’ri burchakli to’rtbur- chak deyiladi. uning barcha burchaklari to’g’ri. dioganallari o’zaro teng. .5. a=2 b=3 c=4 cosa= = cosb= cosc= = ; ; 12-bilet 1. √ √ √ √ (√ ) (√ )(√ ) (√ ) (√ )(√ ) √ √ = 2.y=| | y y=| | x 3 3.cosa=-0,8 ii chorak , demak sina=√ √ tga=sina/cosa=0,6/-0,8=0,75 ctga=1/tga=4/3 javob:tga= 4.har bir tomoniga nisbatan 1 yarimtekislikda yotuvchi ko’pburchak qavariq ko’pburchak deyiladi. qavariq ko’pburchakning dioganallarini toppish formulasi: d= 5.a=3 120 0 +2 0 0 r= 13-bilet 1. hisoblang : 1998=a √ √ √ √ 2. {an} arifmetik progressiyada a2+a9=20 bo‘lsa, s10 ni hisoblang. 1)a2+a9=2a1+9d=a1+a10=20, 2)s10= s10=100 3.ctg( 1/tga=0,5 4.uchburchakning 2ta tomoning o’rtalarini tutushtiruvchi va asosiga parallel kesma uchburchakning o’rta chizig’i deyiladi. 5. b , bundan bo=9 oab=60,ya’ni ao=x ab=2x ob=x√ √ a …

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eyiladi. uchburchaklar o’xshashligining 1-alomati-btb(burchak-tomon-burchak) alomatidir. 5. kesishuvchi vatarlar teoremasiga ko’ra: 3x*4x=12x 2 =16*48 x 2 =4*16 x=2*4=8 ce=3x=3*8=24 ed=4x=32 javob:24;32 17-bilet 1. x+y=5800; 0,1x=0,35y+220, yani x=3,5y+2200 (x-kitob; y-daftar) 3,5y+2200+y=4,5y+2200=5800 4,5y=3600 y=800 x=5800-800=500 2.cheksiz kamayuvchi geometrik progressiya s=150 b1=15 s= 3. 1+tg 2 a= s=a*b*sina s=a*ha=b*hb s= d1*d2*sina 5.s=3*7=21sm 2 18-bilet 1. 100%=21+14=35ta 21=x% x= 6 2.a3+a9=a1+a11=8 s11= 3. sin (α+β)-2sinβ•cosα = 4. ikkita uchburchakning burchaklari teng a tomonlari nisbati mos ravishda teng bo’lsa, bu uchburchaklar o’xshash uchburchaklar deyiladi. uchburchaklar o’xshashligining 3-alomati-ttt(tomon-tomon-tomon) alomatidir. 5. 0 =78 0 b=180 0 -78 0 =102 0 javob:102;78 19-bilet 1. 2. a*(a+5)=266 a 2 +5a-266=0, viyet formulasidan a=14 a+5=19 javob:14;19 3.sina=0,8 ii chorak, cos2a=? cosa= √ √ 4. 5. 2a+a=3a=57 a=19 a√ √ √ √ 20-bilet 1. 2x+3x+4x=9x=639 x=71 4x-2x=2x=142 2. tenglamaning ildizlarini yig‘indisini toping: x 4 -10x 2 +9=0 xossa: keltirilgan kvadrat tenglamada ildizlar doima qarama-qarshi bo’ladi: x1,2= 3,4= 3. 4cosx=2√ tenglik to‘g‘ri bo‘ladigan …

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bo’ladi, shuning uchun ularning ko’paytmasi 1 ga teng. 3. 4.to’g’ri burchakli uchburchakning katetlari kvadratlari yig’indisi gipotenuza kvadratiga teng. uning ikkita o’tkir burchagi yig’indisi 90 0 ga teng. katetlari har doim gipotenuzadan kichik. 5.sin30= 24-bilet 1.a, a+1, a+2, a+3, berilgan. 2(a+a+3)-(a+2-a-1)=2(2a+3)-1=4a+5=57 4a=52 a=13 a=13 a+1=14 a+2=15 a+3=`16 2. x 2 -8x+3=0 x1 2 +x2 2 =(x1+x2) 2 -2x1x2=8 2 -2*3=64-6=58 3. cosa= 4.o’tkir burchakning sinusi: ; cosinusi= tangesi: √ √ √ √ 1.4(x-2)-5(x-3) 2.√ 2 x 2 +5x-6=0 x=1 3.sin15= √ √ √ √ √ √ √ √ 4.ko’pburchakning mos burchaklari teng va mas tomonlari nisbatlari ham teng bo’lsa, bunday ko’pburchaklar o’xshash ko’pburchaklar deyiladi. 5. 5x+13x=18x=360 x=20 0 5x=100 0 50 0 26-bilet 1.kumush=x mis=7x jami=2kg x+7x=8x=2kg x=0,25kg 7x=1,75kg javob:0,25kg, 1,75kg 2. 3. cos √ ( ) ( ) 4.ikki to’g’ri chiziq tekislikda kesishmasa bular, parallel to’g’ri chiziqlar deyiladi. 5.s= √ √ √ √ 27-bilet 1.480=3x+4x+5x=12x x=40 3x=120 4x=160 5x=200 2.(12,5-x):5=(3,6+x):6 …

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9-sinf matematika 1-bilet 1. hisoblang: (1 ( ) +1)* 2. (a+(a-2))*2=p=32 2a-2=16 2a=18 a=9 a-2=7 javob :7sm, 9sm 3. soddalashtiring: tg(-α)ctg(-α)+cos 2 (-α)+sin 2 α tg(-α)ctg(-α)+cos 2 (-α)+sin 2 α= (-tgα)(-ctgα)+ cos 2 α + sin 2 α=1+1=2 4.romb barcha tomonlari teng bo’lgan parallelogramdir. uning dioganallari o’zaro perpendikular kesishadi. 5. a:b=4:3 a+a+b=p=66 , bundan 4x+4x+3x=11x=66 x=6 a=4x=4*6=24 b=3x=3*6=18 javob:24sm, 24sm, 18sm. 2-bilet 1. hisoblang: - - = 2. ( ) )=1 3. agar sinα+cosα= bo‘lsa, sin 3 α+cos 3 α ni hisoblang sin 3 α+cos 3 α=( sinα+cosα)*((sinα+cosα = ( sinα+cosα)* *((sinα+cosα (sinα+cosα = ( ) 4.bir burchagi to’g’ri(9 ) bo’lga uchburchak to’g’ri burchakli uchburchak deyi- ladi. uning katta tomoni tomoni gipotenuza, qolgan tomonlari esa katetlar deb ata- ladi. to’g’r...

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