моддий нуқтанинг эркин тебранма ҳаракати

1477997558_63979.ppt cx x m - = & & 0 2 = + x k x & & m c k = 2 kt c kt c x cos sin 2 1 + = 0 2 0 1 , x c k v c = = kt k v kt x x sin cos 0 0 + = a a sin , cos 2 1 a c a c = = ) sin( a + = kt a x 0 0 2 2 2 0 , v k x tg k v x a o = + = a ) 2 ( ) ( p a a t + + = + + kt t k k p t 2 = …

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