abituriyentlar uchun testlar to'plami

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ahmadjonov azamat unco academy axborotnoma 1996 1 a.96 abituriyentlar uchun variantlashtirilgan testlar to’plami o’qituvchi: ahmadjonov azamat foydalanuvchi: _______________________ ahmadjonov azamat unco academy axborotnoma 1996 2 1-variant 1. 26 25 25 24 24 23 23 22 12 8         ning qiymatini toping. a) 106 b) 1 c) 54 d) 0 2. bir nechta natural sonlarning yig’indisi 75 ga teng. agar shu sonlarning har birida 2 ni ayirib, yig’indi hisoblansa, u 61 ga teng bo’ladi. yig’indida nechta son qatnashgan? a) 5 b) 7 c) 14 d) 8 3. 6,8 0,04 1,65 3,3 5,1 0,16     ning qiymatini toping. a) 6 b) 1 2 c) 2 3 d) 1 6 4. do’konga 96 t karam keltirildi. agar karamning 80% sotilgan bo’lsa, do’konda qancha karam qolgan? a) 16 b) 19,2 c) 24 d) 20,2 5. 1 3 2,5 2 5,2:2 3 5   …

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  ni soddalashtiring. a) 0 b) -2b2 c) -8ab d) -4ab+2b2 18. 4 3 x x    tenglamaning nechta ildizi bor? ahmadjonov azamat unco academy axborotnoma 1996 3 a) 1 b) 2 c) 3 d) ildizga ega emas 19. 2 2 2 1 3 x y xy x y        sistemaning yechimini toping. a) (2; 1) b) (1; 2) c) (2; 2) d) (2; 1), (1; 2) 20. m ning qanday qiymatlarida my+1=m tenglama yechimga ega bo’lmaydi? a) 1 b) 0 c) -1 d) 2 21. (x; y) sonlar jufti 2 5 3 2 4 x y x y      sistemaning yechimi bo’lsa, x-y ni toping. a) 1 b) -1 c) 3 d) 0 22.   3 4 5 2 3 1 1 x x x        tensizliklar sistemasi nechta …

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  tenglamaning ildizlari ko’paytmasini toping. a) 1 b) -2 c) 10 d) 100 6. hech qaysi uchtasi bir to’g’ri chiziqda yotmaydigan 7 ta nuqta berilgan. shu 7 ta nuqta orqali nechta turlicha to’g’ri chiziq o’tkazish mumkin? a) 28 b) 21 c) 42 d) 35 7. ikkita to’g’ri chiziqning kesishishidan hosil bo’lgan uchta burchkaning yig’indisi 3150 ga teng. shu burchaklardan kichigini toping. a) 600 b) 450 c) 700 d) 850 8. to’g’ri burchakli uchburchak kateti 8 sm uning gipotenuzadagi proyeksiyasi esa 6,4 sm. shu uchburchak yuzasi necha sm2 ? a) 25,6 b) 48 c) 51,2 d) 24 9. muntazam uchburchakning balandligi 9 sm. uchburchakka ichki chizilgan aylananing radiusini toping. a) 6 b) 4,5 c) 3 d) 2,5 10. to’g’ri burchakli uchburchakning gipotenuzasi 25 sm, katetlari esa o’zaro 3:4 nisbatda. shu uchburchakning kichik katetini toping. a) 10 b) 12 c) 9 d) 15 11. to’rtburchakning burchaklari o’zaro 3:5:4:6 nisbatda. to’rtburchakning kichik …

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b) 4π c) π√2 d) 8π 19. tekislikka o’tkazilgan perpendikulyar bilan og’ma orasidagi burchak 300, perpendikulyarning uzunligi esa 10 ga teng. og’maning uzunligini toping. a) 20 b) 10√3 c) 20√3 d) 20 3 20.    1;5;3 2; 2;4m va n  vektorlarning skalyar ko’paytmasini hisoblang. a) -24 b) 2 c) 0 d) -10 ahmadjonov azamat unco academy axborotnoma 1996 5 21. muntazam to’rtburchakli piramidaning balandligi 6 sm, apofemasi esa 6,5 sm. piramida asosining perimetrini toping. a) 10 b) 12 c) 24 d) 20 22. asos aylanasining uzunligi 8√𝜋 ga, balandligi 9 sm ga teng bo’lgan konusning hajmini toping. a) 16π b) 24 c) 48 d) 144 23. to’la sirtining yuzi 72 ga teng bo’lgan kubga tashqi chizilgan sharning radiusini toping. a) 3 b) 6 c) 3√3 d) 2√3 24.  2 765tg   ning qiymatini aniqlang. a) −√2 b) 2 √3 c) -2 d) 4 25. agar …

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2,5 c) 2 d) 4 4. ishchining oylik maoshi 350 so’m. agar uning maoshi 30% ortsa, u qancha maosh oladi (so’m)? a) 405 b) 380 c) 1050 d) 455 5. ikki sonning yig’indisi 6,5 ga teng. ulardan biri ikkinchisidan 4 marta kichik. shu sonlarning kattasini toping. a) 6 b) 5 c) 4 d) 5,2 6.    8 6: 2 2 11      ni hisoblang. a) 23 b) -11 c) 143 d) 11 ahmadjonov azamat unco academy axborotnoma 1996 6 7. agar a=-2 va b=3 bo’lsa, a b ga mos javobni toping. a) -1 b) -5 c) 5 d) 1 8. birinchi kuni ish normasining 1 4 qismi bajarildi. ikkinchi kuni birinchi kuni bajarilgan ishning 1 8 qismicha ko’p ish bajarildi. shu ikki kunda qancha ish normasi bajarilgan? a) 9 32 b) 3 40 c) 1 18 d) 17 32 9. 3 1 1 15 …

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ahmadjonov azamat unco academy axborotnoma 1996 1 a.96 abituriyentlar uchun variantlashtirilgan testlar to’plami o’qituvchi: ahmadjonov azamat foydalanuvchi: _______________________ ahmadjonov azamat unco academy axborotnoma 1996 2 1-variant 1. 26 25 25 24 24 23 23 22 12 8         ning qiymatini toping. a) 106 b) 1 c) 54 d) 0 2. bir nechta natural sonlarning yig’indisi 75 ga teng. agar shu sonlarning har birida 2 ni ayirib, yig’indi hisoblansa, u 61 ga teng bo’ladi. yig’indida nechta son qatnashgan? a) 5 b) 7 c) 14 d) 8 3. 6,8 0,04 1,65 3,3 5,1 0,16     ning qiymatini toping. a) 6 b) 1 2 c) 2 3 d) 1 6 4. do’konga 96 …

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