ko`rsatkichli funksiya va ko`rsatkichli tenglama

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1576158982.doc n marta n a a a = - 3 2 1 ...... 1 , , 0 = = = × - + a a a a a a a k n k n k a k n n n n b a b a × = × ) ( km nm m k n b a b a × = × ) ( n n n b a b a = ÷ ø ö ç è æ mn mn m n n b a b a = ÷ ÷ ø ö ç ç è æ n n a a 1 = - n n a a = - 1 n n a b b a ÷ ø ö ç è æ = ÷ ø ö ç è æ - n k n k a a = n km m n k a a = ) ( nm n m …

2 > x 2 2 2 2 > x 2 2 > x 2 > x 2 - x ( ) ( ) ¥ è ¥ - î , 2 2 , x 4 5 , 0 3 2 3 4 + x ) , 0 ( ¥ î x 16 3 3 4 3 4 1 ³ ÷ ø ö ç è æ - ÷ ø ö ç è æ + x x x ÷ ø ö ç è æ 3 4 2 3 4 3 4 16 9 3 4 16 3 3 1 3 4 16 3 1 3 4 3 4 - ÷ ø ö ç è æ ³ ÷ ø ö ç è æ þ ³ ÷ ø ö ç è æ þ ³ × ÷ ø ö ç è æ þ ³ ÷ ø ö ç è æ - ÷ ø ö ç è …

, ya`ni . 3. bo`lsin. a) bo`lganda, bo`ladi. haqiqatda, bu tengsizlikning ikkala tomonini ga bo`lamiz va ni yoki ni hosil qilamiz. shartga ko`ra va bo`lganidan bu tengsizlik-ning tog`riligiga ishonch hosil qilamiz: b) 0 1 bo`lgani uchun dan ni hosil qila-miz. bundan esa yoki va hosil bo`ladi. javob: . 2. 2. tengsizlikni yeching. yechish. tengsizlikni ko`rinishida yozamiz va asos 0,5 -4 yoki hosil bo`ladi. javob: . 3. tengsizlik yechilsin. yechish: 3x=t deb qabul qilsak, 9x=32x=t2 bo`ladi va berilgan teng-sizlikka teng kuchli t2+t-2>0 tengsizlik hosil bo`ladi. uni (t-1)(t+2)>0 ko`rinishida yozib yechim t 1 ni hosil qilamiz. x o`zgaruvchiga o`tsak, 3x 1 ni hosil qilamiz. birinchi tengsizlik yechimga ega emas, chunki barcha haqiqiy uchun 3x>0. ikkinchi tengsizlikni 3x>30 ko`rinishida yozib, bundan x>0 ni hosil qilamiz. javob: . 4. tengsizlikni yeching. yechish: qavsdan ni chiqarib, topamiz: asos bo`lgani uchun x≥-2 ni topamiz. yechim: . 5. tengsizlikni yeching. yechish. tengsizlikni ko`rinishida yozamiz va 6x=t deb …

r kollejlari uchun o`quv qo`llanma. toshkent, “o`qituvchi”, 2001-yil. 4. abduhamidov a. u. va boshqalar. algebra va analiz asoslari. akademik litsey va kasb-hunar kollejlari uchun sinov darsligi. toshkent, “o`qituvchi”, 2001 yil. 5. antonov k. p. va boshqalar. elementar matematika masalalari to`plami. toshkent, “o`qituvchi”, 1975-yil va keyingi nashrlari. 6. skanavi m. n. tahriri ostida. matematikadan masalalar to`plami. toshkent, “o`qituvchi”, 1983-yil va keyingi nashrlari. _1405259525.unknown _1405259590.unknown _1405259622.unknown _1405259638.unknown _1405259646.unknown _1405259654.unknown _1405259658.unknown _1405259660.unknown _1405259662.unknown _1405259663.unknown _1405259664.unknown _1405259661.unknown _1405259659.unknown _1405259656.unknown _1405259657.unknown _1405259655.unknown _1405259650.unknown _1405259652.unknown _1405259653.unknown _1405259651.unknown _1405259648.unknown _1405259649.unknown _1405259647.unknown _1405259642.unknown _1405259644.unknown _1405259645.unknown _1405259643.unknown _1405259640.unknown _1405259641.unknown _1405259639.unknown _1405259630.unknown _1405259634.unknown _1405259636.unknown _1405259637.unknown _1405259635.unknown _1405259632.unknown _1405259633.unknown _1405259631.unknown _1405259626.unknown _1405259628.unknown _1405259629.unknown _1405259627.unknown _1405259624.unknown _1405259625.unknown _1405259623.unknown _1405259606.unknown _1405259614.unknown _1405259618.unknown _1405259620.unknown _1405259621.unknown _1405259619.unknown _1405259616.unknown _1405259617.unknown _1405259615.unknown _1405259610.unknown _1405259612.unknown _1405259613.unknown _1405259611.unknown _1405259608.unknown _1405259609.unknown _1405259607.unknown _1405259598.unknown _1405259602.unknown _1405259604.unknown _1405259605.unknown _1405259603.unknown _1405259600.unknown _1405259601.unknown _1405259599.unknown _1405259594.unknown _1405259596.unknown _1405259597.unknown _1405259595.unknown _1405259592.unknown _1405259593.unknown _1405259591.unknown

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1576158982.doc n marta n a a a = - 3 2 1 ...... 1 , , 0 = = = × - + a a a a a a a k n k n k a k n n n n b a b a × = × ) ( km nm m k n b a b a × = × ) ( n n n b a b a = ÷ ø ö ç è æ mn mn m n n b a b a = ÷ ÷ ø ö ç ç è æ n n a a 1 = - n n a a = - 1 n n a b b a ÷ ø ö ç …

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