ko’rsatkichli va logarifmik tenglamalar sistemasiga oid misollar yechish

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1710189809.pptx î í ì = - = + 1 log log 27 2 3 3 log log 3 3 x y y x x y y x y x x y 3 3 3 3 log log log log 3 = = × ( ) þ ý ü î í ì ÷ ø ö ç è æ 3 1 ; 9 1 , 9 ; 3 ï î ï í ì = = ï î ï í ì = ÷ ø ö ç è æ = × 3 9 1 log 27 3 3 3 log log 3 x y x x y x y y ( ) î í ì = = - + î í ì = = - + î í ì = = × î í ì = = × x y x x x y x x x y x x x y y x …

b: tenglamaniyeching. yechilishi: tenglamaningikkalatomoniniasosgako`ralogarifmlaymiz, ⟺ javob: tenglamaniyeching. yechilishi: aniqlanishsoha ; tengliknio`rinliekanliginibilganholda, tenglamaniikkalatomonini 10 asosgako`ralogarifmlaymiz. belgilashkiritsak, tenglamaniquyidagiko`rinishdayozishimizmumkin. javob: 4-misol 5-misol tenglamaniyeching. yechilishi: aniqlanishsoha. tenglikniikkalatomoninixam 5 asosgako`ralogarifmlasak, . tenglamani chap tamonidagiifodanilogarifm 5 asosliko`rinishgakeltiramiz. .belgilasak, . javob: 6-misol tenglamalar sistemasini yeching. 7-misol yechish.ya’nio‘zgaruvchilarkiritamiz. bundan tenglamalar sistemasiga kelamiz. sistema to‘rtta ildizga ega, ya’ni lekin, shunga e’tibor berish kerakki, shuning uchun ham, faqat sistemalarni qaraymiz. bundan javob: tenglamalar sistemasini yeching. 8-misol yechish. bu turdagi tenglamalar sistemasini yechish uchun sistemadagi har ikki tenglamani o‘nli asosga ko‘ra logarifmlaymiz. endi o‘rniga qo‘yish usuliga ko‘ra natijada ga ega bo‘lamiz. tenglamalar sistemasini yeching. 9-misol yechish. sistemadagi har ikkala tenglamani ikki asosga ko‘ra logarifmlaymiz va quyidagi sistemaga keltiramiz. javob ∅ (bo‘sh to‘plam). sistema yechimga ega emas. 10-misol tenglamalar sistemasini yeching. yechish. sistemadagi birinchi tenglamaning har ikki tomoni x darajaga ko‘tariladi: 11-misol tenglamalar sistemasini yeching. yechish . sistemadagi ikkinchi tenglamaning har ikki tomoni у darajaga ko‘tariladi: mustaqil yechish uchun misollar 1. 2. …

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1710189809.pptx î í ì = - = + 1 log log 27 2 3 3 log log 3 3 x y y x x y y x y x x y 3 3 3 3 log log log log 3 = = × ( ) þ ý ü î í ì ÷ ø ö ç è æ 3 1 ; 9 1 , 9 ; 3 ï î ï í ì = = ï î ï í ì = ÷ ø ö ç è æ = × 3 9 1 log 27 3 3 3 log log 3 x y x x y x y y ( ) î í ì = = - + î í ì = = …

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