abituriyentlar uchun variantlashtirilgan testlar to’plami

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ahmadjonov azamat unco academy axborotnoma 2001 1 a.01 abituriyentlar uchun variantlashtirilgan testlar to’plami o’qituvchi: ahmadjonov azamat foydalanuvchi: _______________________ ahmadjonov azamat unco academy axborotnoma 2001 2 ahmadjonov azamat unco academy axborotnoma 2001 3 1-variant 1.           2 4 1 1,08 : 0,25: 0, 3 25 7 3 ni hisoblang. a) 1 b) 4 3 c) 1 3 d) 2 3 2. 4 7 8 11 12 15 ... 96 99        yig’indini hisoblang. a) -75 b) -80 c) -72 d) -63 3.    3,2 62 1, 15 ni hisoblang. a) 2,2(47) b) 2,247 c) 2,(12) d) 2,(1) 4. 5 2 6 5 2 6   ni hisoblang. a) 2 2 b) 4 6 c) 2 d) 2 2 5. 101 103, 99 105a b    va 19,9c  sonlarini kamayish tartibida …

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soat ga ko’p bo’lsa, yo’lovchi poyezdining tezligi qanchaga teng bo’ladi? a) 24 b) 25 c) 27 d) 30 15. a ning qanday qiymatlarida   25 4 10 0a x x a    tenglamaning ildizlari turli ishorali bo’ladi? a) (-1; 5) b) (-4; 0) c) (-5; 1) d) (0; 1) ahmadjonov azamat unco academy axborotnoma 2001 4 16. 2 1 4x   tengsizlikni yeching. a) [-4; 4] b)    ; 4 4;    c)    ;2 6;   d)  2;6 17. 2 25 5 5 17x x x x     tenglamaning ildizlari yig’indisini toping. a) 6 b) 3 c) -5 d) -3 18. agar 3 1 2 0x x     bo’lsa, 3 2 1x x  ifodaning qiymatini toping. a) 24 b) 22 c) -1 d) 18 19. agar 21 3 x y …

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variant 1. 1 cos ln 1 cos x y x    funksiyaning hosilasini toping. a) 1 sin x b) 2 sin x c) tgx d) ctgx ahmadjonov azamat unco academy axborotnoma 2001 5 2. agar   2 2 x x f x x    bo’lsa,  2f  ning qiymatini toping. a) 0,625 b) 0,5 c) 0,25 d) -0,5 3. 2 3 2y x x   funksiyaning grafigiga absissasi x=0 nuqtada urinma o’tkazilgan. shu urinmaning absissasi x=11 bo’lgan nuqtaning ordinatasini toping. a) 36 b) 33 c) 35 d) 32 4. 5 33 5 3y x x   funksiyaning ekstremum nuqtalaridagi qiymatlari yig’indisini toping. a) -9 b) -6 c) -8 d) -4 5. 2 2xy x e funksiyaning o’sish oraliqlarini toping. a)  ; 1  b)  1;1 c)    ; 1 0;1   d)  0;1 6.   …

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n boshlab eng kamida nechtasini olganda, ularning kosinuslari yig’indisi nolga teng bo’ladi? a) 18 b) 17 c) 19 d) 35 ahmadjonov azamat unco academy axborotnoma 2001 6 16. 2 2 2 2 cos sin ctg tg       ni soddalashtiring. a) 6ctg  b) 4ctg  c) 4tg  d) 6ctg  17. 5 3 arcsin 5 arctg  ning qiymatini hisoblang. a)  4 b) 6  c) 3  d) 2  18.  24sin 1 cos2 1 cos2x x x   tenglamani yeching. a) ,n n z  b) ; , 3 n n n z      c) , 3 n n z     d) ; 2 , 3 n n n z      19. agar 1 1 sin cos 3 2 va     bo’lsa,    …

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gan jismning hajmini toping. a) 6 b) 4 c) 11 2  d) 8 28. konusning balandligi 10 ga, o’q kesimi uchidagi burchagi 1200 ga teng. konus hajmining konus yon sirtiga nisbatini toping. a) 5 3 b) 2 c) 2 3 d) 3 2 ahmadjonov azamat unco academy axborotnoma 2001 7 29. muntazam to’rtburchakli piramidaning uchidagi tekis burchagi 600 ga teng. shu piramidaning yon qirrasi va asosi orasidagi burchakni toping. a) 150 b) 300 c) 450 d) 600 30. konus asosining radiusi 2 ga, o’q kesimining uchidagi burchagi 600 ga teng. shu konusga tashqi chizilgan muntazam uchburchakli piramidaning hajmini toping. a) 12 b) 12 3 c) 18 3 d) 24 3-variant 1. 1 dan 50 gacha bo’lgan toq sonlar yig’indisning kvadrat ildizini hisoblang. a) 45 b) 35 c) 25 d) 40 2. n ning qanday eng kichik natural qiymatida 2 1n  soni 33 ga qoldiqsiz bo’linadi? a) 7 b) …

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ahmadjonov azamat unco academy axborotnoma 2001 1 a.01 abituriyentlar uchun variantlashtirilgan testlar to’plami o’qituvchi: ahmadjonov azamat foydalanuvchi: _______________________ ahmadjonov azamat unco academy axborotnoma 2001 2 ahmadjonov azamat unco academy axborotnoma 2001 3 1-variant 1.           2 4 1 1,08 : 0,25: 0, 3 25 7 3 ni hisoblang. a) 1 b) 4 3 c) 1 3 d) 2 3 2. 4 7 8 11 12 15 ... 96 99        yig’indini hisoblang. a) -75 b) -80 c) -72 d) -63 3.    3,2 62 1, 15 ni hisoblang. a) 2,2(47) b) 2,247 c) 2,(12) d) 2,(1) 4. 5 2 6 5 2 6 …

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