27-oktabr

buxoro viloyat vobkent tuman 11-umumta`lim maktabi boshlang’ich sinf o’qituvchisi akramova kamolaning 3-sinf matematika fanidan tayyorlagan taqdimoti mavzu : yuzlikdan o‘tib ko‘paytirish takrorlaymiz: 1-topshiriq 64·2=128 174·2=348 242·3=726 161·6=966 3·82=246 2·352=704 4·152=608 8·121= 968 2-topshiriq 2 ta o‘ramda 242 m sim bor. shunday 5 ta o‘ramda qancha sim bo‘ladi? 6 ta o‘ramda­chi? qisqa sharti: 2 ta o‘ramda- 242 m sim 5 ta o‘ramda -?m sim 6 ta o‘ramda -?m sim 3-topshiriq x·40=320 640:y=80 z·90= 450 x=320:40 y=640:80 z=450:90 x= 8 y=8 z=5 t:8·40=320 t:640:8=80 t:5·90=450 yechish: 1. 242:2=121 (m) 2.121x5=605(m) 3.121x6=726(m) javob:5 ta o`ramda 605 m, 6 ta o`ramda 726m 4-topshiriq yechish: 1. 3x6=18 (cm) 2. 2x2=4(cm) 3. 18-4=14 (cm) javob:14 cm 5-topshiriq aylanaga har birining orasi...

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