3=sinf.ayirishga doir masalalar.2-mavzu.

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3-sinf fan:matematika mavzu:ayirishga doir masalalar 2-mavzu dars shiori! matematika fanlar ichra shoh, uning sirlaridan bo`laylik ogoh! sinf ishi: avtomobil shahargacha 156 km masofani bosib o`tdi.qaytishda yana shuncha masofano bosib o`tadi.avtomabil shaharga borib kelguncha necha km masofani bosib o`tadi? oila necha kishidan iborat? (3 kishidan) 2) ular necha yoshda? (ota 35 yosh, ona 32 yoshda) 3) qizchaning yoshi nechada? (ota va onasining yoshlari yig‘indisidan 57 yosh kichik) 35 + 32 = 67 67 – 57 = 10 (yosh) oʻsish tartibida: 217 m, 349 m, 408 m, 535 m, 637 m, 762 m, 976 m. kamayish tartibida: 976 m, 762 m, 637 m, 535 m, 408 m, 349 m, 217 m. dam olish daqiqasi: tadbir uchun nechta shardan gul tayyorlandi? (183 ta) 2) tadbir yakunida nechta shar qoldi? (171 ta) 3) yasalgan gulda shar nechtaga kamayganini qanday bilish mumkin? 183 – 171 = 12 ta javob: yasalgan gulda shar 12 taga kamaygan. …
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3-sinf fan:matematika mavzu:ayirishga doir masalalar 2-mavzu dars shiori! matematika fanlar ichra shoh, uning sirlaridan bo`laylik ogoh! sinf ishi: avtomobil shahargacha 156 km masofani bosib o`tdi.qaytishda yana shuncha masofano bosib o`tadi.avtomabil shaharga borib kelguncha necha km masofani bosib o`tadi? oila necha kishidan iborat? (3 kishidan) 2) ular necha yoshda? (ota 35 yosh, ona 32 yoshda) 3) qizchaning yoshi nechada? (ota va onasining yoshlari yig‘indisidan 57 yosh kichik) 35 + 32 = 67 67 – 57 = 10 (yosh) oʻsish tartibida: 217 m, 349 m, 408 m, 535 m, 637 m, 762 m, 976 m. kamayish tartibida: 976 m, 762 m, 637 m, 535 m, 408 m, 349 m, 217 m. dam olish daqiqasi: tadbir uchun nechta shardan gul tayyorlandi? (183 ta) …

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