ii_chet_8_klass_algebra_sorβ„–_4_obsheobr_original_1_variant

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klass _______ imya, familiya _________________________data _____ algebra 8 klass sor β„–4 1-variant 1. sravnite chisla π‘Ž i 𝑏 . (4 balla) 1) π‘Ž βˆ’ 𝑏 = βˆ’1,2 2) π‘Ž βˆ’ 𝑏 = (βˆ’3)4 otvet: _______________________________________________ 2. obe chasti dannogo neravenstva na ukazannoe chislo: (4 balla) 1) βˆ’8π‘Ž 2 i 𝑏 > 5 , to π‘Žπ‘(π‘Ž2 + 𝑏2) > 270 . (6 ballov) otvet: _______________________________________________ 5. reshite uravnenie: (6 ballov) 1) 26π‘₯+4 = 64 2) (0,3)2βˆ’3π‘₯ = 0,027 otvet: _______________________________________________ summarniy ball uchenika: ____________ proveril prepodavatel: _________________________ ________(podpis) kriterii otsenki β„– ball otvet deskriptor 1 4 1) π‘Ž 𝑏 za kajdoe pravilnoe sravnenie po 2 balla, vsego 4 balla. 2 4 1) βˆ’4π‘Ž 2 za kajdiy pravilniy otvet po 2 balla, vsego 4 balla. 3 5 1) esli napishet: π‘Ž > 5 , 1 ball; 2) napishet π‘Ž > 5 i naxodit 𝑏 > 15 , 2 balla; 3)iz π‘Ž > …
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klass _______ imya, familiya _________________________data _____ algebra 8 klass sor β„–4 1-variant 1. sravnite chisla π‘Ž i 𝑏 . (4 balla) 1) π‘Ž βˆ’ 𝑏 = βˆ’1,2 2) π‘Ž βˆ’ 𝑏 = (βˆ’3)4 otvet: _______________________________________________ 2. obe chasti dannogo neravenstva na ukazannoe chislo: (4 balla) 1) βˆ’8π‘Ž 2 i 𝑏 > 5 , to π‘Žπ‘(π‘Ž2 + 𝑏2) > 270 . (6 ballov) otvet: _______________________________________________ 5. reshite uravnenie: (6 ballov) 1) 26π‘₯+4 = 64 2) (0,3)2βˆ’3π‘₯ = 0,027 otvet: _______________________________________________ summarniy ball uchenika: ____________ proveril prepodavatel: _________________________ ________(podpis) kriterii otsenki β„– ball otvet deskriptor 1 4 1) π‘Ž 𝑏 za kajdoe pravilnoe sravnenie po 2 balla, vsego 4 balla. 2 4 1) βˆ’4π‘Ž 2 za kajdiy pravilniy otvet po 2 balla, …

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