prezident maktabi imtihon savollari

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presidential schools admissions test - sample items with explained answers test a: problem solving key: d justification for every one 500 som banknote, there will be two 200 som banknotes and six 100 som banknotes. so, for every one 500 som banknote there will be a total of 9 banknotes adding up to 1500 som ( (1 x 500) + (2 x 200) + (6 x 100)). 12000/1500 = 8, so there will 8 lots of 9 banknotes, and 8 x 9 = 72. 1 anora was counting her money and found that she had 12000 som. she was able to put all of her banknotes into three piles of 100 som notes, 200 som notes and 500 som notes. she found that there were three times as many 100 som notes as 200 som notes, and twice as many 200 som notes as 500 som notes. how many banknotes …

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y: b justification b is the only appearance which is not possible. each of the others can be made by cutting one of the corners. test a: critical thinking 4 lots of people in the world do not have clean water to drink. + drinking dirty water can easily make people ill. + governments have a duty to help people stay healthy. = ________________________________________________ which one of these sentences should go in the space above? a people should not drink dirty water. b everyone should try to stay healthy. c lots of people have to travel a long way to find drinking water. d governments never do their duty. e governments should make sure people have clean drinking water. key: e justification from the first two sentences we can conclude that a lack of clean drinking water is likely to be affecting people’s health. with the addition of the third …

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ur has cheated on other tests before this one. key: b justification if kobe is able to deduce only from the fact that mansur got full marks that mansur must have cheated, it must not have been possible for mansur to score full marks without cheating. if this is not the case, what kobe says is not justified. distractors a would be sufficient grounds for kobe’s claim, but goes beyond what has to be true, as we are only told kobe’s result. c does not have to be true – it may be that the test was quite easy for the other students. d does not have to be true – it may be that mansur excels in other subjects, or would score full marks on a much easier maths test. e does not have to be true – it may be that this is the first time mansur has …

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– if anything it may weaken it, although the explorer has not actually advocated taking unnecessary risks. e pre-empts a possible objection to the claim (i.e. that young people should not be encouraged to engage in risky behaviour), but does not strengthen the claim independently of this. 7 before setting out on a long climb, a group of climbers was told by the guide: “anyone who has not started climbing by 4:00 am will not reach the summit.” if the guide’s prediction was right, which one of these sentences must have been true? a all the climbers who started before 4:00 am reached the summit. b some of climbers who started before 4:00 am reached the summit. c none of the climbers who started after 4:00 am reached the summit. d only the climbers who reached the summit started before 4:00 am. e all the climbers who did not reach …

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iginally the numbers of cows, sheep, and chickens were the same, this gives x + x/2 + 2x/3 = 26, where x equals the original number of cows. solving for x gives 12 cows originally, and adding the extra 3 cows gives a final answer of 15. 2 below is a summary of all the second-hand cars sold by bargain cars during 2012 and 2013: jan feb mar apr may jun jul aug sep oct nov dec 2012 85 83 98 102 118 135 88 97 116 83 125 128 2013 123 106 87 114 90 106 124 113 131 77 92 75 which month of 2013 saw the biggest increase in sales compared with the previous month? a april b june c july d september e november key: a justification there was an increase of 27 from march to april 2013; this was the only increase of 20 or …

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presidential schools admissions test - sample items with explained answers test a: problem solving key: d justification for every one 500 som banknote, there will be two 200 som banknotes and six 100 som banknotes. so, for every one 500 som banknote there will be a total of 9 banknotes adding up to 1500 som ( (1 x 500) + (2 x 200) + (6 x 100)). 12000/1500 = 8, so there will 8 lots of 9 banknotes, and 8 x 9 = 72. 1 anora was counting her money and found that she had 12000 som. she was able to put all of her banknotes into three piles of 100 som notes, 200 som notes and 500 som notes. …

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