matematika 9-sinf

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matematika 9-sinf / matematika 9-klass # savol a b c d ball 1. agar π‘₯2 + 𝑦2 = 2 bolsa, π‘₯6 + 𝑦6 + 6π‘₯2𝑦2 yig’indini toping. esli π‘₯2 + 𝑦2 = 2 nayti summu: π‘₯6 + 𝑦6 + 6π‘₯2𝑦2 12 16 6 8 2 2. (4√6 + √39 + 2√26 + 6)(4√6 + √39 βˆ’ 2√26 βˆ’ 6) hisoblang. (4√6 + √39 + 2√26 + 6)(4√6 + √39 βˆ’ 2√26 βˆ’ 6) vichislit βˆ’15 βˆ’6 βˆ’5 βˆ’10 2 3. 0, (π‘Žπ‘π‘Žπ‘) davriy kasr 29 33 ga teng bo’lsa, 2π‘Ž + 3𝑏 ni toping. (π‘Ž, 𝑏 βˆ’ raqamlar). periodicheskaya drob 0, (π‘Žπ‘π‘Žπ‘) ravna 29 33 . hayti 2π‘Ž + 3𝑏. (π‘Ž, 𝑏 βˆ’tsifri) 37 35 29 39 1 4. 𝑛 ning qanday qiymatlarida 𝑓(π‘₯) = √π‘₯ βˆ’ 7 βˆ’ βˆšπ‘› βˆ’ 4π‘₯ βˆ’ π‘₯2 funksiya aniqlanish sohasi bitta nuqtadan iborat bo’ladi? pri kakom 𝑛 oblast opredeleniya funktsii 𝑓(π‘₯) = √π‘₯ …
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+ 𝑏𝑐 + π‘π‘Ž (π‘Ž + 𝑏 + 𝑐)2 3(π‘Žπ‘ + 𝑏𝑐 + π‘π‘Ž) 3 10. π‘Ž ning qanday qiymatlarida |π‘₯βˆ’2| π‘₯βˆ’2 = (π‘₯ βˆ’ π‘Ž)2 tenglama yagona yechimga ega bo’ladi? pri kakix znacheniyax π‘Ž, uravnenie |π‘₯βˆ’2| π‘₯βˆ’2 = (π‘₯ βˆ’ π‘Ž)2 imeet tolko odno reshenie? (βˆ’βˆž; βˆ’3) [3; +∞) (1; 3] (βˆ’3; 3] 3 11. 𝐴𝐡𝐢 uchburchakka ichki chizilgan aylana 𝐴𝐡 va 𝐴𝐢 tomonlarga 𝑀 va 𝑁 nuqtalarda urinadi. agar 𝐴𝐡 = 4, 𝐴𝐢 = 3, 𝐡𝐢 = 2 bo’lsa, 𝐴𝑀𝑁 uchburchak yuzini toping. vpisannaya v treugolnik 𝐴𝐡𝐢 okrujnost kasaetsya storon 𝐴𝐡 i 𝐴𝐢 v tochkax 𝑀 i 𝑁 sootvetstvenno. naydite ploshad treugolnika 𝐴𝑀𝑁, esli 𝐴𝐡 = 4, 𝐴𝐢 = 3, 𝐡𝐢 = 2 25√15 64 16√15 27 15√15 16 25√15 32 3 12. 𝑦 = 6,86 3,14 π‘₯ + 6,86 3,14 va 𝑦 = 3,14 6,86 π‘₯ + 13,14 6,86 to’g’ri chiziqlar (π‘₯; 𝑦) nuqtada kesishadi. 𝑦 βˆ’ …
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tlari yig’indisi eng kichik qiymatni qabul qiladi? pri kakix znacheniyax π‘Ž summa kvadratov korney uravneniya π‘₯2 βˆ’ 2π‘Žπ‘₯ + π‘Ž2 βˆ’ 6π‘Ž βˆ’ 28 = 0 yavlyaetsya naimenshey. 1 βˆ’3 βˆ’1 βˆ’2 2 19. (π‘₯2 βˆ’ π‘₯ + 1): ((π‘₯2 + π‘₯βˆ’2)2 + 2(π‘₯ + π‘₯βˆ’1)2 βˆ’ 3)0,5 hisoblang, bunda π‘₯ = 0, (6) (π‘₯2 βˆ’ π‘₯ + 1): ((π‘₯2 + π‘₯βˆ’2)2 + 2(π‘₯ + π‘₯βˆ’1)2 βˆ’ 3)0,5 vichislit pri π‘₯ = 0, (6). 9 38 3 19 7 38 4 19 1 20. kitob sahifalarini raqamlash uchun kitob sahifalari sonidan 2 marta ko’p raqam ishlatildi. agar kitob sahifalari 500 tadan kam bo’lsa, sahifalar sonini toping. dlya numeratsii nekotorogo chisla stranits potrebovalos v 2 raz bolshe tsifr chem bilo stranits. skolko bilo stranits, esli eto menshe 500? 111 108 152 153 2
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matematika 9-sinf / matematika 9-klass # savol a b c d ball 1. agar π‘₯2 + 𝑦2 = 2 bolsa, π‘₯6 + 𝑦6 + 6π‘₯2𝑦2 yig’indini toping. esli π‘₯2 + 𝑦2 = 2 nayti summu: π‘₯6 + 𝑦6 + 6π‘₯2𝑦2 12 16 6 8 2 2. (4√6 + √39 + 2√26 + 6)(4√6 + √39 βˆ’ 2√26 βˆ’ 6) hisoblang. (4√6 + √39 + 2√26 + 6)(4√6 + √39 βˆ’ 2√26 βˆ’ 6) vichislit βˆ’15 βˆ’6 βˆ’5 βˆ’10 2 3. 0, (π‘Žπ‘π‘Žπ‘) davriy kasr 29 33 ga teng bo’lsa, 2π‘Ž + 3𝑏 ni toping. (π‘Ž, 𝑏 βˆ’ raqamlar). periodicheskaya drob 0, (π‘Žπ‘π‘Žπ‘) ravna 29 33 . hayti 2π‘Ž + 3𝑏. (π‘Ž, 𝑏 βˆ’tsifri) 37 35 29 39 1 4. 𝑛 …

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