nazorat ishlari

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1 5-sinf. masalaning yechimini baholash uchun namuna. masalan: i poyezd 4 soatda 336 km, avtobus 3 soatda 126 km yo’l bosdi. avtobusning tezligi poyezd tezligidan necha marta kam? yechish: 1. poyezd tezligi nimaga teng? 336 km : 4 soat = 84 (km/soat). 2. avtobus tezligi nimaga teng? 126 km : 3 soat = 42 (km/soat) 3. avtobus tezligi poyezd tezligidan necha marta kam? 84 km/soat : 42 km/soat = 2 (marta) javob: avtobus tezligi poyezd tezligidan 2 marta kam. baho: 5 ball yechish tartibli va to’g’ri bajarilgan. javob to’g’ri. ii. poyezd 4 soatda 336 km, avtobus 3 soatda 126 km yo’l bosdi. avtobusning tezligi poyezdning tezligidan necha marta kam? yechish: 1. poyezdning tezligi nimaga teng? 336 : 4 = 84 (km/soat) 2. avtobusning tezligi nimaga teng? 126 : 3 = 42 (km/soat) 3. avtobusning tezligi poyezd tezligidan necha marta kam? 84 : 42 = 2 (marta) javob: 2 marta. baho: …

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di. avtobus tezligi poyezd tezligidan necha marta kam? yechish: 1) 336 : 4 = 84; 2) 126 : 3 = 41; 84 : 41 = (bo’linmaydi) javob chiqmadi. baho: 1 ball. yechish yo’li to’g’ri, lekin yechishning har bir qadamiga qo’yilgan savolning formulirovkasi berilmagan, ikkinchi qadamda bo’lish noto’g’ri bajarilgan. shuning uchun noto’g’ri javob hosil bo’ldi. 5-sinf 3 1 – nazorat ishi i variant 1. sonlarni raqamlar bilan yozing: 60 million 5 ming 40. 2. as kesma chizing va unda k nuqtani belgilang. ak va ks kesmalarni o‘lchang. 3. kilometr va metrlarga ifodalang: 4567 m. 4. koordinata nurida (son nuruda) 995 va 1003 sonlari orasida yotuvchi natural sonlarni yozing. 5. amallarni balaring: 49 · 23 + 3920 : 28 ii variant 1. sonlarni raqamlar bilan yozing: 7 million 37 ming 8. 2. vd kesma chizing va unda e nuqtani belgilang. be va de kesmalarni o‘lchang. 3. kilometr va metrlarga ifodalang: 5346 m. …

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inatasi nimaga teng? 3. ukasi x yoshda, akasi esa undan 5 yosh katta. ifoda tuzing va 12x da uning qiymatini toping. 4 4. 28 + m + 72 ifodani soddalashtiring, 87m da uning qiymatini toping. 5. 0, 2, 4, 6 raqamlaridan ularni takrorlamasdan nechta ikki xonali son turish mumkin? ularni yozing. ii variant 1. 437 dan katta va 457 dan kichik 7 raqami bilan tugagan sonni toping. 2. koordinata nurini chizing va unda m(3) nuqtani belgilang, bu nuqtadan o’ngga 7 birlik kesma qo’ying va t nuqtani belgilang. t nuqtaning koordinatasi nimaga teng? 3. ukasi x yoshda, akasi esa undan 5 yosh katta. ifoda tuzing va 10x da uning qiymatini toping. 4. 15149n ifodani soddalashtiring, 63n da uning qiymatini toping. . 5. 1, 3, 5, 7 raqamlaridan ularni takrorlamasdan nechta ikki xonali son turish mumkin? ularni yozing. 4 – nazorat ishi i variant 1. qulay usul bilan hisoblang: 125 · 80 …

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oping: (432 : 12 + 53 · 33) : 35 - 15. 3. ifodaning qiymatini toping: a) 22 55  ; b) 473  4. tenglamani yeching: 20 – m = 17. 5. ikki sonning yig‘indis 549. sonlardan biri ikkinchisidan 8 marta kam. shu sonlarni toping. 6 – nazorat ishi i variant 1. agar t = 12 soat, s = 240 km bo‘lsa, yol formulasi bo‘yicha v ning qiymatini toping. 2. to‘g‘ri to‘rtburchakning bo‘yi 28 sm, kengligi (eni) esa, 7 marta kam. to‘g‘ri to‘rtburchakning yuzi nimaga teng? 3. a) kvadrat metrlarda ifodalang: 5 ga; 18 a; b) gektarlarda ifodalang: 420 000 2m . 4. to‘g‘ri burchakli parallelepipedning 112 2sm , uzunligi 8 sm, eni 7 sm. balandligini toping. 5. a) santimetr kublarda ifodalang: 5 3dm 635 3sm ; b) detsimetr kublarda ifodalang:: 6 3m 580 3dm ii variant 1. agar t = 5 sekund, s = 15 m. bo‘lsa, yo’l …

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b) surati 4 ga teng barcha noto‘g‘ri kasrlarni. 4. amallarni bajaring: a) 25 4 25 9 25 17  ; b)        19 7 19 8 19 18 . 5. ifodaning qiymatini toping: (432 : 12 + 53∙33) : 35 – 15. 8 – nazorat ishi i variant 1. 4 m 7 ta yubka tikildi. har yubkada qanchada mato ketdan? 2. bo‘linmani kasr ko‘rinishida yozing: a) 4: 7; b) 8 : 11, c) 9 : 1 va kasrni bo‘linma ko‘rinishida yozing: 7 28 , 5 5 , 6 11 3. noto‘g‘ri kasr ko‘rinishida yozing: 7 3 4; 3 2 5; 2 1 3 . 4. kasrlarning butun qismini ajrating: . 77 77 ; 7 18 ; 4 5 5. ifodaning qiymatini toping: a) 12 11 2 12 5 1 12 7 4  ; b) 12 7 58  . ii variant 1. 7 …

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1 5-sinf. masalaning yechimini baholash uchun namuna. masalan: i poyezd 4 soatda 336 km, avtobus 3 soatda 126 km yo’l bosdi. avtobusning tezligi poyezd tezligidan necha marta kam? yechish: 1. poyezd tezligi nimaga teng? 336 km : 4 soat = 84 (km/soat). 2. avtobus tezligi nimaga teng? 126 km : 3 soat = 42 (km/soat) 3. avtobus tezligi poyezd tezligidan necha marta kam? 84 km/soat : 42 km/soat = 2 (marta) javob: avtobus tezligi poyezd tezligidan 2 marta kam. baho: 5 ball yechish tartibli va to’g’ri bajarilgan. javob to’g’ri. ii. poyezd 4 soatda 336 km, avtobus 3 soatda 126 km yo’l bosdi. avtobusning tezligi poyezdning tezligidan necha marta kam? yechish: 1. poyezdning tezligi nimaga teng? 336 : 4 = 84 …

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