9-sinf algebra 6-bsb 1-var.@chsb_uzb

[image: ] 9 sinf algebradan 6– bsb savollari i variant 1. ifodaning son qiymatini toping: (4 ball) cos 1845° + ctg 495° − sin 1035° 2. ko‘paytmaga aylantiring: (5 ball) 1 − 2 cos 𝛼 3. soddalashtiring: (4 ball) cos 𝛼 + cos 2𝛼 + cos 3𝛼 2 cos 𝛼 + 1 4. agar arifmetik progressiyada 𝑎3 = −13 va 𝑎7 = −41 bo‘lsa, uning 𝑛 – hadi formulasini toping. (6 ball) 5. 7 dan boshlab 318 gacha bo‘lgan barcha juft sonlarning yig‘indisini toping. (318 ham yig‘indiga kiradi). (6 ball) image1.jpeg

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