attestatsiya 2024 ink 26 - 20240427_055641

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alijonov sirojiddin ms va attestatsiya attestatsiya 2024 attestatsiya 2024 1. ( ) 2f x mx= + , ( ) 4g x x m= + va ( ) ( )2 3f g= bo’lsa m ni toping. @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 2. o’tkir burchagi 30 bo’lgan parallelogram tomonlari 2:3 nisbatda. paralellogramm perimetri 60 ga teng bo’lsa, parallelogranm yuzini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 3. ( ) 4 3 0 84x kx dx+ = bo’lsa, k ni toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 4. 3 ta lift bor. birinchi liftga 3 ta odam, ikkinchi va uchinchi liftga 2 tadan odam chiqsa bo’ladi. 7 ta odamni necha xil usukl bilan bu liftlarga chiqarish mumkin. @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 5. ( ) ( )2 36 16 log 1f x x x x= − + + + …

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di? alijonov sirojiddin ms va attestatsiya attestatsiya 2024 13. ikki natural sonni 5 ga bo’lganda mos ravishda 1 va 3 qoldiq qolsa, bu sonlarni yig’indisini 5 ga bo’lgandagi qoldiqni toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 14. uchburchakning tomonlari 6 2 va 4 ga teng. agar ular orasidagi burchak 45 ga teng bo’lsa uchburchak uchinchi tomonini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 15. 20 6015 20+ ifodani 13 ga bo’lgandagi qoldiqni toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 16. 2 2 14 32 0 1 2 x x x − + + = − − tenglamani yeching. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 17. radiusi 6 3 ga teng bo’lgan sharga ichki chizilgan eng katta hajmli slindr asosining radiusini toping? alijonov sirojiddin ms va attestatsiya attestatsiya 2024 18. radiusi 6 3 ga teng bo’lgan sharga ichki chizilgan eng katta hajmli konus asosining radiusini toping? alijonov …

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kg qorishmaning 60% sement. shu qorishmaga qancha qum qo’shilsa 40% sement bo’ladi. @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 27. 7 7 45 0,4 0,1 6 15 100   + − +    alijonov sirojiddin ms va attestatsiya attestatsiya 2024 28. 108 75 48 147 27 12 + + + + alijonov sirojiddin ms va attestatsiya attestatsiya 2024 29. ( ); 180ekuk a b = , ( ); 9ekub a b = bo’lsa, a b+ ning eng kichik qiymatini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 30. arifmetik progressiyada n m k p+ = − bo'lsa, n m k pa a a a+ = + bo’ladimi? @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 31. muntazam uchburchakli kesik pramidaning asoslari 3 va 7. unga shar ishki chizilgan. piramida yon sirtini yuzini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 …

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mat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 38. 2 2 4 18 18 x x x x − − + funksiyaning barcha boshlang’ich funksiyalarini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 39. 3y x= , 0y = va 1y = chiziqlar bilan chegaralangan soxani ox o’qi atrofida aylantirishdan hozil bo’lgan jism hajmini toping? @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 40. parallelopipedni o’lchamlari 8,12,15 ga teng bo’lsa to’la sirtini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 41. ( )1 3 1 6 1f x x− − = + , ( )( )2 2 1f g m− = + va ( ) 4 1g x x= + bo'lsa, m ni toping? alijonov sirojiddin ms va attestatsiya attestatsiya 2024 42. agar ( ) 2f x mx= + va ( ) 4g x x m= + uchun ( )( )1 2 3g f− = bo’lsa, m …

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) 2 2 0 2 9xf x dx− = bo’lsa, s2 ni toping. @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 51. prizmaning qirralari soni 35 ta bo’lsa, yoqlari sonini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 52. ( ) 1 1 x f x x + = − bo’lsa, ( )f x ni toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 53. 2 2 8 41 25 5 x x + −      tengsizlikni butun yechimlari nechta? @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 54. nechta 4 xonali sonda 2 ham, 3 ham ishtirok etmaydi? alijonov sirojiddin ms va attestatsiya attestatsiya 2024 55. 1006 ni oxirgi 2 ta raqamini toping? @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 56. ( )4; 1m − , ( )2;3n − , ( ); yp x , ( …

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alijonov sirojiddin ms va attestatsiya attestatsiya 2024 attestatsiya 2024 1. ( ) 2f x mx= + , ( ) 4g x x m= + va ( ) ( )2 3f g= bo’lsa m ni toping. @attestatsiya_ms_group @gmat_gre_group https://t.me/attestatsiya_ms_group https://t.me/gmat_gre_group alijonov sirojiddin ms va attestatsiya attestatsiya 2024 2. o’tkir burchagi 30 bo’lgan parallelogram tomonlari 2:3 nisbatda. paralellogramm perimetri 60 ga teng bo’lsa, parallelogranm yuzini toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 3. ( ) 4 3 0 84x kx dx+ = bo’lsa, k ni toping. alijonov sirojiddin ms va attestatsiya attestatsiya 2024 4. 3 ta lift bor. birinchi liftga 3 ta odam, ikkinchi va uchinchi liftga 2 tadan odam chiqsa bo’ladi. 7 ta odamni necha xil usukl bilan bu liftlarga …

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