anorganik kimyo

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tasks are included in the collection and exercises on the basic concepts and laws, a structure of atoms and molecules, chemical connection, chemical kinetics and catalysis, to thermochemical and oxidation-reduction reactions, solutions, electrolytic dissociation and electrolysis, to the basic classes of inorganic connections and also on modern representations about a nature of acids and the bases. the tasks included in the collection are placed in a direction from simple to complex. the same tasks are given with decisions. at the end of the book of problems are given complex and tasks of chemical olympiads with decisions. the collection is intended for students of the academic licea, professional colleges, pupils of the senior classes of comprehensive schools, for the persons studying chemistry independently, and also to the entrants acting in higher educational institutions. the collection may be useful to students of younger rates of high schools, and also to teachers. anorganik …
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27kg). 1.11. oltingugurt atomining massasini hisoblang. (javob: 53,15·10-27 kg). 1.12. 46 g massali natriyda qancha natriy moddasi bor? yechish. masala (1.4) tenglama asosida yechiladi: mol. 1.13. 4,4 g massali kalsiydagi modda miqdorini toping. (javob: 0,11 mol). 1.14. 11,2 g massali temirda qancha temir moddasi bor? (javob: 0,2 mol). 1.15. 14,2 g (nh4)2c2o4.h2o dagi modda miqdorini toping. (javob: 0,1 mol). 1.16. 4,86 g kaliy geksaxloroplatinat (k2ptcl6) dagi modda miqdorini toping. (javob: 0,01 mol). 1.17. modda miqdori 0,25 mol bo‘lgan kaliy sulfat (k2so4) necha gramm keladi? yechish. masalani yechish uchun (1.4) formuladan foydalanamiz: m=vm=0,25.174=43,5 g. 1.18. 0,1 mol karbonat angidrid (co2) necha g keladi? (javob: 4,4 g). 1.19. 0,5 mol kalsiy fosfat [ca3(po4)2] necha g keladi? (javob: 155 g). 1.20. 17,2 g gips (caso4.2h2o) da nechta oltingugurt va kislorod atomlari bor? yechish. masalani yechish uchun avvalo (1.4) formula asosida modda miqdori topiladi. so‘ngra modda miqdori avogadro soni va moddadagi atomlar soniga ko‘paytiriladi: …
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y fosfatning qancha massasida 0,34 g fosfindagicha fosfor atomi bo‘ladi? (javob: 1,64 g). kimyoviy modda tarkibidagi elementning va aralashma tarkibidagi moddaning massa ulushi 1.27. kmno4 tarkibidagi elementlarning massa ulushlarini hisoblang. yechish: masalani yechish uchun (1.9) formuladan foydalanamiz: yoki 24,7 %; yoki mn=34,8 %; yoki o=40,5 %. 1.28. napo3 tarkibidagi elementlar atomlarining massa ulushlarini toping. (javob: na - 22,55 %; p -30,39 %; o - 47,06 %). 1.29. na2s2o3 tarkibidagi elementlarning massa ulushlarini toping. (javob: na - 29,11 %; s - 40,51 %; o - 30,38 %). 1.30. magniy sulfat kristallgidrati (mgso4·7h2o) tarkibidagi suvning massa ulushini toping. (javob: 51,22 %). 1.31. tarkibida 35 % feo va 65 % fe2o3 bo‘lgan 120 g aralashma tarkibidagi temirning massasini hisoblang. yechish: eng avvalo (1.5) formula yordamida aralashma tarkibidagi har bir tarkibiy qismning massasi hisoblanadi. mfeo=m=0,35.120=42 g, m(fe2o3)=m=0,65·120=78 g. masalaning davomi proporsiya bilan yechilsa: mfeo=72, bo‘lganligi uchun 72:42=56:x; x=42.56/72=32,67 g fe bor. 160:78=112:x; x=54,6 g. …
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an oksidlangan magniy metali kukuni tarkibida 2 % kislorod bo‘lsa, namuna tarkibidagi magniy metalining massa ulushini toping. (javob: 95 %). 1.36. tarkibida 0,85 % bog‘langan kislorod bo‘lgan alyuminiy metali parchasidagi metallning massa ulushini hisoblang. (javob: 98,2 %). kimyoviy birikmalarning formulalarini chiqarish 1.37. tarkibida 39,7 % kaliy, 27,9 % marganets va 32,4 % kislorod bo‘lgan moddaning eng oddiy formulasini toping. yechish: moddaning umumiy formulasini kxmnyoz deb olsak, . demak, moddaning formulasi k2mno4 ekan. 1.38. agar oksid tarkibidagi fosforning massa ulushi 56,4 % va kislorodniki 43,6 % bo‘lsa, oksidning eng oddiy formulasini toping. yechish: pxoy formuladagi indekslar quyidagicha topiladi: bu sonlarni eng kichigiga bo‘lganda ham butun sonlar hosil bo‘lmaydi. shuning uchun umumiy bo‘luvchi 0,9 topiladi: demak, moddaning eng oddiy formulasi p2o3 ekan. 1.39. oksidlar tarkibiga kiruvchi elementlarning massa ulushlari mos ravishda quyidagicha a) s=50,0%, b) mn=49,6%, c) c=42,8%, d) pb=86,6%, e) cu=80,0 % bo‘lsa, ularning eng oddiy formulalarini toping. (javob: a – …
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batga to‘g‘ri keladigan qiymatni har bir atomning nisbiy atom massasiga bo‘lamiz: demak, marvaridning eng oddiy formulasi caco3 ekan. 1.44. chumoli kislotada vodorod, uglerod va kislorodning massa nisbatlari 1:6:16. bu moddaning eng oddiy formulasini toping. (javob: hcooh). 1.45. temir oksidida temir massasining kislorod massasiga nisbati 7:3 bo‘lsa, oksidning eng oddiy formulasi qanday bo‘ladi? (javob: fe2o3). 1.46. oltingugurt oksidida oltingugurt atomi massasining kislorod atomi massasiga nisbati 2:3 bo‘lsa, shu oksidning eng oddiy formulasi qanday bo‘ladi? (javob: so3). 1.47. 20 g massali oltingugurt 30 g massali kislorodga to‘g‘ri kelsa, shu oksidning eng oddiy formulasi qanday bo‘ladi? yechish: masalani yechish uchun nisbat tuziladi va har bir elementning modda miqdorlari topiladi: 0,625:1,875=1:3. demak, oksidning formulasi: so3. 1.48. 18 g massali alyuminiy 6 g massali uglerod bilan birikma hosil qilgan bo‘lsa, shu moddaning eng oddiy formulasini toping. (javob: al4c3). 1.49. oksid tarkibidagi 12,8 g misga 1,6 g kislorod to‘g‘ri keladi. shu oksidning eng oddiy formulasini toping. …

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tasks are included in the collection and exercises on the basic concepts and laws, a structure of atoms and molecules, chemical connection, chemical kinetics and catalysis, to thermochemical and oxidation-reduction reactions, solutions, electrolytic dissociation and electrolysis, to the basic classes of inorganic connections and also on modern representations about a nature of acids and the bases. the tasks included in the collection are placed in a direction from simple to complex. the same tasks are given with decisions. at the end of the book of problems are given complex and tasks of chemical olympiads with decisions. the collection is intended for students of the academic licea, professional colleges, pupils of the senior classes of comprehensive schools, for the persons studying …

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