ratsional ko’rsatkichli darajali funksiya. irratsional ko’rsatkichli darajaning mavjudligi

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1662970094.doc 3 2 1 n a a a ..... . +¥ ¥ ; [ ) +¥ ; 0 +¥ ® +¥ ® n a n a 1 q p q p p q ) 1 q p q p a 1 = - 0 2 1 r q a 1 1 1 1 p p r qq aaa æö == ç÷ ç÷ èø 2 2 2 1 p p r qq aaa æö == ç÷ ç÷ èø 1 r a r 2 a ) ( n r ) ( n r a n r r ) ( n r a ) ( n r a / n / n r 2 1 a 1 bo’lganda r dan a tengsizlik kelib chiqadi. haqiqatan, r dan r1 1 bo’lganda bo’ladi. shu sababli , dan 1 bo’lsa, ketma-ketlik ham o’suvchi bo’ladi. ( dan kattaroq ratsional r son olsak a 1 bo’lganda, bo’lganda ekanligi …

i sanab o’tamiz. 1. y=logax logarifmik funksiyaning aniqlanish sohasi (0;+) dan, qiymatlar to’plami (- ;+ ) dan iborat, 2. y=logax funksiya a>1 da o’suvchi, a 0 bo’lsa, d(f)=[0;+ ), f(x)= bo’lsa, d(f)=(- ;0) (0;+ ), f(x)=xn bo’lib, n bo’lsa, d(f)=(- ;+ ). ( irratsional son bo’lsa, d(f)=(0;+ ) deb qaraladi. y=x( va d(y)=(0;+ ) deb, uning ushbu xossalarini sanab o’tamiz: 1. (>0 bo’lganda darajali funksiya o’suvchi, ( 0 bo’lganda darajali funksiya o’suvchi, (<0 bo’lganda kamayuvchi bo’ladi; 2. y=x( funksiya (0;+ ) da uzluksiz. lnx va ex funksiyalarning har biri uzluksiz bo’lgani uchun y=x( murakkab funksiya ham uzluksiz bo’ladi. adabiyotlar: 1) азларов. т., мансуров. х. “математик анализ” 1т: 1994,2т. 1995. 2) xикматов а.x., турдиев т., “математик анализ” тошкент: 1т, 1990 . 3) введение в maple. математический пакет для всех. в.н.говорухин, в.г.цибулин, мир, 1997 4) пакет символьных вычислений maple v. г.в. прохоров и др. "петит", 1997 5) математическая система maple v. в.п.дьяконов, …

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1662970094.doc 3 2 1 n a a a ..... . +¥ ¥ ; [ ) +¥ ; 0 +¥ ® +¥ ® n a n a 1 q p q p p q ) 1 q p q p a 1 = - 0 2 1 r q a 1 1 1 1 p p r qq aaa æö == ç÷ ç÷ èø 2 2 2 1 p p r qq aaa æö == ç÷ ç÷ èø 1 r a r 2 a ) ( n r ) ( n r a n r r ) ( n r a ) ( n r a / n / n r 2 1 a 1 bo’lganda r dan a tengsizlik kelib …

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ratsional ko’rsatkichli darajali funksiya. irratsional ko’rsatkichli darajaning mavjudligi

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