raschyotno-gaficheskaya rabota. variant №26

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raschyotno-gaficheskaya rabota. variant №26 var ris r1 r2 r3 r4 r5 r6 e1 e2 e3 ik1 ik2 ik3 № № om om om om om om v v v a a a 26 1-3 6 19,5 13,5 15 7,5 9 - 16,2 15 - 0,4 0 predvaritelnie vichisleniya: 1.preobrazuem istochnik toka v ekvivalentniy istochnik eds i opredelim summarnuyu eds v vetvi: e'2=e2+ ik2r2=16,2+0,419,5=24 v e'3=e3+ ik3r3=15+013,5=15 v 2.ekvivalentnaya elektricheskaya sxema tsepi imeem vid: 3.sostavlyaem uravneniya dlya uzlov tsepi po 1 zakonu kirxgofa: a: -i1+i2-i6=0 c: i3-i4+i1=0 b: i6+i5-i3=0 d: i4-i5-i2=0 4.sostovlyaem uravneniya dlya kontorov tsepi po 2 zakonu kirxgova: i (abda) i6r6-i5r5+i2r2=e'2 ii (bcdb) i3r3+i4r4+i5r5=e'3 iii (adca) -i2r2-i4r4-i1r1=-e'2 a) reshenie po metodu konturnix tokov (mkt) 1.sxema: 2.sostavlyaem uravneniya dlya uzlov tsepi po 1 zakonu kirxgofa: a: -i1+i2-i6=0 c: i3-i4+i1=0 b: i6+i5-i3=0 d: i4-i5-i2=0 sostovlyaem uravneniya dlya kontorov tsepi po 2 zakonu kirxgova: i (abda) i6r6-i5r5+i2r2=e'2 ii (bcdb) i3r3+i4r4+i5r5=e'3 iii (adca) …

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,5- -17691,75=18987,75 v2 =21870+7020-3510-(5703,75-7290+12960)=25380- -11373,75=14006,25 v2 =31104+2193,75+2700-(-16848-1350-8100)=-26210,25+ +26298=87,75 v2 8.vichislyaem znacheniya konturnix tokov cherez determinanti: ii===0,79 a iii===0,5827 a iiii===0,0036 a 9.ispolzuya uravneniya iz punkta 3, opredelyaem toka vetvey cherez naydennie znacheniya konturnix tokov: i1=-iiii=-0,0036 a i4=iii-iiii=0,5827-0,0036=0,5791 a i2=ii-iiii=0,79-0,0036=0,7864 a i5=iii-ii=0,5827-0,79=-0,2073 a i3=iii=0,5827 a i6=ii=0,79 a proverka poluchennix znacheniy: 1.po 1 zakonu kirxgofa: a: -i1+i2-i6=0,0036+0,7864-0,79=0 b: i6+i5-i3=0,79-0,2073-0,5827=0 c: i3-i4+i1=0,5827-0,5791-0,0036=0 d: i4-i5-i2=0,5791+0,2073-0,7864=0 2.po 2 zakonu kirxgofa: i (abda) i6r6-i5r5+i2r2=0,799+0,20737,5+0,786419,5=24 v ii (bcdb) i3r3+i4r4+i5r5=0,582713,5+0,579115-0,20737,5=15 v iii (adca) -i2r2-i4r4-i1r1=-0,786419,5-0,579115+0,00366=-24 v otvet (po mkt) i1=-0,0036 a i4=0,5791 a i2=0,7864 a i5=-0,2073 a i3=0,5827 a i6=0,79 a v) reshenie po metodu uzlovix potentsialov (mup) 1.sxema: 2.prinimaem potentsial proizvolno vibrannogo uzla ravnim nulyu. dlya ostalnix uzlov sostavlyaem uravneniya 1 zakonu kirxgofa: : -i1+i2-i6=0 : i3-i4+i1=0 : i6+i5-i3=0 =0 3.virajaem toki vetvey cherez uzlovie potentsiali: i1=(-)g1 i4=(-)g4 i2=(-+e'2)g2 i5=(-)g5 i3=(-+e'3)g3 i6=(-)g6 4.zamenyaem toka vetvey v uravneniyax po 1 zakonu kirxgofa uzlovimi potentsialami: -(-)g1+(-+e'2)g2-(-)g6=0 (-)g6+(-)g5-(-+e'3)g3=0 (-+e'3)g3+(-)g1-(-)g4=0 5.vipolnim preobrazovaniya, …

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1111 om-1 g13=-g1=-0,1667 om-1 g21=-g6=-0,1111 om-1 g22=g6+g5+g3=0,1111+0,1333+0,0740=0,3184 om-1 g23=-g3=-0,0740 om-1 g31=-g1=-0,1667 om-1 g32=-g3=-0,0740 om-1 g33=g3+g1+g4=0,0740+0,1667+0,0667=0,3074 om-1 8.vichislyaem osnovnoy i dopolnitelnie determinanti: gde =0,0322+(-0,0013)+(-0,0013)-(0,0088+0,0038+ +0,0018)=0,0296-0,0144=0,015 om-3 =-0,1205-0,0091+0,0136-(0,0589-0,0379- -0,0067)=-0,116-0,0143=-0,1303 a om-2 =0,1122-0,015-0,0205-(0,0308+0,0420+ +0,0270)=0,0767-0,0998=-0,0234 a om-2 =-0,1163+0,0205-0,0101-(0,0653-0,0137- -0,0270)=-0,1059-0,0246=-0,1305 a om-2 9.naxodim potentsiali uzlov: ===-8,6 v ===-1,56 v ===-8,7 v 9.postavlyaem znacheniya potentsialov i provodimostey v uravneniya 3, naxodim toki vetvey: i1=(-)g1=(-8,7+8,68)0.1667=-0,0033 a i2=(-+e'2)g2=(-8,68-0+24)0,0513=0,7859 a i3=(-+e'3)g3=(-8,7+1,56+15)0,0740=0,5816 a i4=(-)g4=(0+8,7)0,0667=0,5802 a i5=(-)g5=(-1,56-0)0,1333=-0,2079 a i6=(-)g6=(-1,56+8,68)0,1111=0,7910 a proverka poluchennix znacheniy: 1.po 1 zakonu kirxgofa: a: -i1+i2-i6=0,0033+0,7859-0,7910=0 b: i6+i5-i3=0,7910-0,2079-0,5816=0 c: i3-i4+i1=0,5816-0,5802-0,0033=0 d: i4-i5-i2=0,5802+0,2073-0,7859=0 2.po 2 zakonu kirxgofa: i (abda) i6r6-i5r5+i2r2=0,79109+0,20797,5+0,785919,5=24 v ii (bcdb) i3r3+i4r4+i5r5=0,581613,5+0,580215-0,20797,5=15 v iii (adca) -i2r2-i4r4-i1r1=-0,785919,5-0,580215+0,00336=-24 v otvet (po mup) i1=-0,0033 a i4=0,5802 a i2=0,7859 a i5=-0,2079 a i3=0,5816 a i6=0,7910 a s) reshenie po metodu nalojeniya (metod ekvivalentnogo generatora) 1.polojim, chto sxemu prisutstvuet tolko odin generator eds e'2. uprostim sxemu tex por, toka ne ostanetsya odin kontur: 2.vichislim znacheniya soprotivleniy: r13=r1+r3+=6+13,5+=24,9 om r34=r3+r4+=13,5+15+=62,25 om r14=r1+r4+=6+15+=27,67 om …

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4268,9843=7,5702 v proverka: e'2=ur2+ur14=16,4307+7,5702=24 3.2.dlya sxemu 1.5: ur14=ur136345=ure=i'2re=0,84268,9843=7,5702 v i'r14===0,2736 a i'r136345===0,5690 a proverka: i'2=i'r14+i'r136345=0.2736+0,5690=0,8426 a 3.3.dlya sxemu 1.4: ur345=i'r136345r345=0,56906,6935=3,8087 v ur136=i'r136345r136=0,56906,6106=3,7614 v proverka: ure=ur345+ur136=3,8087+3,7614=7,5702 v 3.4.dlya sxemu 1.3: ur136=i'r136345r136=0,56906,6106=3,7614 v ur345=i'r136345r345=0,56906,6935=3,8087 v i'6===0,4179 a i'5===0,5078 a 3.5.dlya sxemu 1, vichislim ostalnie toka iz 1 zakonom kirxgofa: (dlya uzla d): i'4+i'5-i'2=0 i'4=-i'5+i'2=-0,5078+0,8426=0,3348 a (dlya uzla a): i'2-i'6-i'1 =0 i'1= i'2-i'6=0,8426-0,4179=0,4247 a (dlya uzla b): i'6-i'5-i'3=0 i'3= i'6-i'5=0,4179-0,5078=-0,0899 a proverka: (dlya uzla c): i'3-i'4+i'1=-0,0899-0,3348+0,4247=0 i'1=0,4247 a i'4=0,3348 a i'2=0,8426 a i'5=0,5078 a i'3=-0,0899 a i'6=0,4179 a 4.polojim, chto sxemu prisutstvuet tolko odin generator eds e'3. uprostim sxemu tex por, toka ne ostanetsya odin kontur: 5.vichislim znacheniya soprotivleniy: r16=r1+r6+=6+9+=17,7692 om r26=r2+r6+=19,5+9+=57,75 om r12=r1+r2+=6+19,5+=38,5 om r265===6,6379 om r124===10,7944 om r265124=r265+r124=6,6379+10,7944=17,4323 om re====8,7995 om 6.poetapno v obratnom poryadke vichislim neizvestnie znacheniyax: 6.1.dlya sxemu 4.6: i''3=i''e===0,6726 a ur3=i''3r3=0,672613,5=9,0801 b ur16=ur265124=ure=i''3re=0,67268,7995=5,9185 v proverka: e'3=ur3+ur16=9,0801+5,9185=15 6.2.dlya sxemu 4.5: ur16=ur265124=ure=i''3re=0,67268,7995=5,9185 v i''r16===0,3330 a i''r265124===0,3395 a proverka: i''3=i''r16+i''r265124=0,3330+0,3395=0,6726 a …

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d): i''4-i''5-i''2=0 i''2=i''4-i''5=0,2443-0,3004=-0,0561 a (dlya uzla b): i''6+i''5-i''3 =0 i''6= i''3-i''5=0,6726-0,3004=0,3722 a (dlya uzla a): i''2-i''1-i''6=0 i''1= i''2-i''6=-0,0561-0,3722=-0,4283 a proverka: (dlya uzla c): i''3-i''4+i''1=0,6726-0,2443-0,4283=0 i''1=-0,4283 a i''4=0,2443 a i''2=-0,0561 a i''5=0,3004 a i''3=0,6726 a i''6=0,3722 a 7.istinnie znacheniyax tokov v vetvyax sxemi poluchim putyom nalojeniya 2 sxem: i1=i'1+i''1=0,4247-0,4283=-0,0036 a i2=i'2+i''2=0,8426-0,0561=0,7865 a i3=i'3+i''3=-0,0899+0,6726=0,5827 a i4=i'4+i''4=0,3348+0,2443=0,5791 a i5=-i'5+i''5=-0,5078+0,3004=-0,2074 a i6=i'6+i''6=0,4179+0,3722=0,7901 a proverka poluchennix znacheniy: 1.po 1 zakonu kirxgofa: a: -i1+i2-i6=0,0036+0,7865-0,7901=0 b: i6+i5-i3=0,7901-0,2074-0,5827=0 c: i3-i4+i1=0,5827-0,5791-0,0036=0 d: i4-i5-i2=0,5791+0,2074-0,7865=0 2.po 2 zakonu kirxgofa: i (abda) i6r6-i5r5+i2r2=0,79019+0,20747,5+0,786519,5=24 v ii (bcdb) i3r3+i4r4+i5r5=0,582713,5+0,579115-0,20747,5=15 v iii (adca) -i2r2-i4r4-i1r1=-0,786519,5-0,579115+0,00366=-24 v otvet (po metodu nalojeniya) i1=-0,0036 a i4=0,5791 a i2=0,7865 a i5=-0,2074 a i3=0,5827 a i6=0,7901 a opredelim padeniya napryajeniya v soprotivleniyax sxema: u1=i1r1=-0,00366=-0,0216 b u2=i2r2=0,786519,5=15,3367 b u3=i3r3=0,582713,5=7,8664 b u4=i4r4=0,579115=8,6865 b u5=i5r5=-0,20747,5=-1,5555 b u6=i6r6=0,79019=7,1109 b svodnaya tablitsa rezultatov vichisleniy po 3 metodam: metod rascheta i1, a i2, a i3, a i4, a i5, a i6, a konturniy tok -0,0036 0,7864 0,5827 …

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raschyotno-gaficheskaya rabota. variant №26 var ris r1 r2 r3 r4 r5 r6 e1 e2 e3 ik1 ik2 ik3 № № om om om om om om v v v a a a 26 1-3 6 19,5 13,5 15 7,5 9 - 16,2 15 - 0,4 0 predvaritelnie vichisleniya: 1.preobrazuem istochnik toka v ekvivalentniy istochnik eds i opredelim summarnuyu eds v vetvi: e'2=e2+ ik2r2=16,2+0,419,5=24 v e'3=e3+ ik3r3=15+013,5=15 v 2.ekvivalentnaya elektricheskaya sxema tsepi imeem vid: 3.sostavlyaem uravneniya dlya uzlov tsepi po 1 zakonu kirxgofa: a: -i1+i2-i6=0 c: i3-i4+i1=0 b: i6+i5-i3=0 d: i4-i5-i2=0 4.sostovlyaem uravneniya dlya kontorov tsepi po 2 zakonu kirxgova: i (abda) i6r6-i5r5+i2r2=e'2 ii (bcdb) i3r3+i4r4+i5r5=e'3 iii (adca) -i2r2-i4r4-i1r1=-e'2 a) reshenie po metodu konturnix tokov (mkt) 1.sxema: 2.sostavlyaem uravneniya dlya uzlov …

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