kimyo sinovi 9-sinf yechimi

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9-sinf (yechim) 1-masala (jami – 7 ball) 5zn + 14hno3 = 5zn(no3)2 + no2 + 3no + 7h2o (4 ball) n = (14/5)∙(3,25/65) = 0,14 mol (3 ball) 2-masala (jami – 7 ball) 1. pb3(co3)2(oh)2 (4 ball) 2. pb3(co3)2(oh)2 + 3h2s = 3pbs + 2co2 + 4h2o (1,5 ball) 2pb3(co3)2(oh)2 + о2 = 2pb3o4 + 4co2 + 2h2o (1,5 ball) 3-masala (jami – 10 ball) 1. (4 ball) 2. natriy karbonat 0°с va 100°с dagi to’yingan eritmalarining konsentratsiyalarini hisoblab olamiz: (2 ball) olinishi kerak bo’lgan suvning massasi x, na2co3·10h2o niki esa y bo’lsin: ikki noma’lumli tenglamani yechsak, x = 2,07 g (suv); y = 10,45 g (na2co3·10h2o). (4 ball) 4-masala (jami – 10 ball) 1. tuz tarkibi csauhaln bo’lsa, . demak, 0,229n = 24,3/a(hal) → a(hal) = 24,3/(0,229n) = 106,1/n → n = 3 bo’lsa, a(hal) = 35,4 va bu cl ning nisbiy atom massasiga juda yaqin. demak, tuz tarkibidagi …
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9-sinf (yechim) 1-masala (jami – 7 ball) 5zn + 14hno3 = 5zn(no3)2 + no2 + 3no + 7h2o (4 ball) n = (14/5)∙(3,25/65) = 0,14 mol (3 ball) 2-masala (jami – 7 ball) 1. pb3(co3)2(oh)2 (4 ball) 2. pb3(co3)2(oh)2 + 3h2s = 3pbs + 2co2 + 4h2o (1,5 ball) 2pb3(co3)2(oh)2 + о2 = 2pb3o4 + 4co2 + 2h2o (1,5 ball) 3-masala (jami – 10 ball) 1. (4 ball) 2. natriy karbonat 0°с va 100°с dagi to’yingan eritmalarining konsentratsiyalarini hisoblab olamiz: (2 ball) olinishi kerak bo’lgan suvning massasi x, na2co3·10h2o niki esa y bo’lsin: ikki noma’lumli tenglamani yechsak, x = 2,07 g (suv); y = 10,45 g (na2co3·10h2o). (4 ball) 4-masala (jami – 10 ball) 1. tuz tarkibi csauhaln bo’lsa, . …

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