masalalar yechish. 10-sinf, 30-mavzu

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1730834280.pptx /docprops/thumbnail.jpeg презентация powerpoint mavzu: masalalar yechish. fizika 𝑥=𝐴𝑠𝑖𝑛(𝜔_0 𝑡+𝜑_0 ), 𝜔=2𝜋𝜈=2𝜋/𝑇 , 𝑇=1/𝜈=𝑡/𝑁 𝜗=𝐴𝜔_0 𝑐𝑜𝑠(𝜔_0 𝑡+𝜑_0) 𝑎=−𝐴𝜔_0^2 𝑠𝑖𝑛⁡(𝜔_0 𝑡+𝜑_0) prujinali mayatnikda: 𝜔_0=√(𝑘/𝑚) 𝑇=2𝜋√(𝑚/𝑘) 𝐸_𝑝=(𝑘𝑥^2)/2; 𝐸_𝑘=(𝑚𝜗^2)/2 〖;𝐸〗_(𝑡𝑜‘𝑙𝑎)=𝐸_𝑘+𝐸_𝑝=(𝑘𝐴^2)/2 matematik mayatnikda: 𝜔=√(𝑔/𝑙) ; 𝑇=2𝜋√(𝑙/𝑔) masala nuqtaning garmonik tebranishlari amplitudasi 6 cm, maksimal tezligi esa 1,2 m/s bo‘lsa, tebranishlarning siklik chаstotasini toping. formula: da yechish: javob: berilgan: topish kerak: masala qonun bo‘yicha tebranayotgan nuqta harakat boshidan necha sekund o‘tgach, muvozanat vaziyatidan boshlab amplitudaning yarmiga teng bo‘lgan masofaga siljiydi? tebranish davri 24 s. formula va yechish: ; javob: berilgan: topish kerak: masala moddiy nuqta muvozanat vaziyatidan 4 cm ga siljiganda uning tezligi 6 cm/s ga, 3 cm ga siljiganda esa 8 cm/s ga teng. siklik chastotani toping. formula: yechish: javob: berilgan: topish kerak: masala matematik mayatnikning siklik chastotasi qandaydir sayyorada 5 rad/s ni tashkil etadi. agar mayatnikning uzunligi 0,4 m bo‘lsa, shu sayyoradagi og‘irlik kuchining tezlanishini toping. formula: g yechish: g javob: berilgan: topish …

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1730834280.pptx /docprops/thumbnail.jpeg презентация powerpoint mavzu: masalalar yechish. fizika 𝑥=𝐴𝑠𝑖𝑛(𝜔_0 𝑡+𝜑_0 ), 𝜔=2𝜋𝜈=2𝜋/𝑇 , 𝑇=1/𝜈=𝑡/𝑁 𝜗=𝐴𝜔_0 𝑐𝑜𝑠(𝜔_0 𝑡+𝜑_0) 𝑎=−𝐴𝜔_0^2 𝑠𝑖𝑛⁡(𝜔_0 𝑡+𝜑_0) prujinali mayatnikda: 𝜔_0=√(𝑘/𝑚) 𝑇=2𝜋√(𝑚/𝑘) 𝐸_𝑝=(𝑘𝑥^2)/2; 𝐸_𝑘=(𝑚𝜗^2)/2 〖;𝐸〗_(𝑡𝑜‘𝑙𝑎)=𝐸_𝑘+𝐸_𝑝=(𝑘𝐴^2)/2 matematik mayatnikda: 𝜔=√(𝑔/𝑙) ; 𝑇=2𝜋√(𝑙/𝑔) masala nuqtaning garmonik tebranishlari amplitudasi 6 cm, maksimal tezligi esa 1,2 m/s bo‘lsa, tebranishlarning siklik chаstotasini toping. formula: da yechish: javob: berilgan: topish kerak: masala qonun bo‘yicha tebranayotgan nuqta harakat boshidan necha sekund o‘tgach, muvozanat vaziyatidan boshlab amplitudaning yarmiga teng bo‘lgan masofaga siljiydi? tebranish davri 24 s. formula va yechish: ; javob: berilgan: topish kerak: masala moddiy nuqta muvozanat vaziy...

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