fizika. yakuniy nazorat [2-variant]

DOCX 2 pages 47.1 KB Free download

Page preview (2 pages)

Scroll down 👇
1 / 2
fizika. yakuniy nazorat [2-variant] 1. jism 2 m radiusli aylana bo'ylab 𝜀 = 1.5 𝑟𝑎𝑑 𝑠2 burchak tezlanish bilan aylanmoqda. uning tangensial tezlanishini hisoblang. (m/s2) a) 1.5 b) 2.5 c) 3 d) 4 2. jism tezligining vaqtga bog’liqligi 𝑣 𝑡 = 2𝑡 − 0.25𝑡2 ko’rinishida, uning 4 s da bosib o’tadigan masofasini hisoblang. (m) a) 10.7 b) 12.5 c) 3.5 d) 4.5 3. jismning massasi 3 kg va ishqalanish koeffitsienti 0.1 ga teng bo'lsa. jismga ta'sir qilishi mumkin bo'lgan ishqalanish kuchining maksimal qiymatini hisoblang. a) 3 n b) 2 n c) 4 n d) 1 n 4. massasi 1 kg bo’lgan jism 20 sm radiusli aylana bo’ylab tekis aylanma harakat qilmoqda. jismning aylanish o’qiga nisbatan inersiya momentini hisoblang. (kgm2)𝑅 𝑅 uning bosimi qanday bo'lishini hisoblang. (kpa) a) 75.8 b) 80 c) 90 d) 60 14. issiqlik mashinasi isitgichda 400 kj energiya oldi va 200 kj foydali ish bajardi. uning foydali …
2 / 2
0.135 b) 0.625 c) 1.303 d) 0.192 8. 9 kg massali barabanga ip o’ralgan bo’lib, uning uchiga 2 kg massali yuk osilsin. yukning tezlanishi topilsin. baraban bir jinsli silindr deb hisoblansin. (m/s2) a) 3 b) 2 c) 1 d) 4 9. massasi 64 g bo'lgan kislorodning modda miqdorini hisoblang. kisorod uchun molyar massasi 32 g/mol ga teng. (mol) a) 5 b) 2 c) 14 d) 1 10. temperaturasi 400 k bo'lgan kislorod molekulalarining o'rtacha arifmetik tezligini hisoblang. kislorodning molyar massasi 32 g/mol. a) 514.4 m/s b) 505.3 m/s c) 558.2 m/s d) 600.3 m/s 11. hajmi 8.31 litr bo'lgan idishda 200 k temperaturali 2 mol ideal gaz bor. uning idishga berayotgan o'rtacha bosimini hisoblang. (kpa) a) 400 b) 300 c) 831 d) 200 12. temperaturasi 400 k bo'lgan geliy molekulalarining eng katta ehtimollik tezligini hisoblang. geliyning molyar massasi 4 g/mol. (m/s) a) 1303.7 b) 1289.2 c) 1234.3 d) 2105.4 13. …

Want to read more?

Download all 2 pages for free via Telegram.

Download full file

About "fizika. yakuniy nazorat [2-variant]"

fizika. yakuniy nazorat [2-variant] 1. jism 2 m radiusli aylana bo'ylab 𝜀 = 1.5 𝑟𝑎𝑑 𝑠2 burchak tezlanish bilan aylanmoqda. uning tangensial tezlanishini hisoblang. (m/s2) a) 1.5 b) 2.5 c) 3 d) 4 2. jism tezligining vaqtga bog’liqligi 𝑣 𝑡 = 2𝑡 − 0.25𝑡2 ko’rinishida, uning 4 s da bosib o’tadigan masofasini hisoblang. (m) a) 10.7 b) 12.5 c) 3.5 d) 4.5 3. jismning massasi 3 kg va ishqalanish koeffitsienti 0.1 ga teng bo'lsa. jismga ta'sir qilishi mumkin bo'lgan ishqalanish kuchining maksimal qiymatini hisoblang. a) 3 n b) 2 n c) 4 n d) 1 n 4. massasi 1 kg bo’lgan jism 20 sm radiusli aylana bo’ylab tekis aylanma harakat qilmoqda. jismning aylanish o’qiga nisbatan inersiya momentini hisoblang. (kgm2)𝑅 𝑅 …

This file contains 2 pages in DOCX format (47.1 KB). To download "fizika. yakuniy nazorat [2-variant]", click the Telegram button on the left.

Tags: fizika. yakuniy nazorat [2-vari… DOCX 2 pages Free download Telegram