yuldasheva shahrixon, 37-maktab, matematika 4-sinf

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namangan viloyati xtb namangan tuman xtb bo‘limiga qarashli 37-sonli umumiy o’rta ta’lim maktabining boshlang‘ich sinf o‘qituvchisi yuldasheva shahrixonning 4-sinf matematika fanidan “tezlik.vaqt . masofa“ mavzusida tayyorlagan taqdimoti 2019-2020 o‘quv yili propowerpoint.ru dars qoidalari faol bo‘ling diqqat qiling xato qilmang tartib saqlang propowerpoint.ru uyga vazifa: 279-masala 5 ta bir xil qutining massasi 30 kg. 30 ta shunday qutining massasi qancha? 5ta quti 30kg 30ta shunday quti ? kg propowerpoint.ru yechimi: 30:5=6 kg 30·6=180kg javob: 180kg propowerpoint.ru 280-misol 10sr08kg–4sr12kg= 12km750 m + 4 km 075 m= 47 650 – 857 – 6 599= 5 538 – (14 + 778)= yechimi: 10sr08kg–4sr12kg=1008kg-412kg=596kg 12km750 m + 4 km 075 m=12750m-4075m=8675m 47 650 – 857 – 6 599=46793-6599=40194 5 538 – (14 + 778)=5538-792=4746 propowerpoint.ru tezlik.vaqt.masofa propowerpoint.ru 281-masala 1) velosipedchi 48 km masofani soatiga bir xil tezlik bilan yurib, 4 soatda bosib o‘tdi. velosipedchi bir soatda necha kilometr yo‘l bosgan? propowerpoint.ru propowerpoint.ru esda tuting s …
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3= 11km/soat javob : 11km/soat propowerpoint.ru propowerpoint.ru savol: agar vaqt va masofa ma’lum bo‘lsa, tezlikni qanday topish mumkin? propowerpoint.ru javob: harakat tezligini topish uchun masofani vaqtga bo‘lish kerak. propowerpoint.ru 283-masala uchta sisternada 10 427 lbenzin bor edi. birinchi sisternada 4574 l, ikkinchisida birinchisidagiga qaraganda 1696lkam benzin bor.uchinchi sisternada necha litr benzin bor? 10 427 litr benzin 4574 litr 1- sisternadan 1696 litr kam,? propowerpoint.ru 283-masala yechish: 4574- 1696=2878 l (2-sisternadagi benzin) 4574+2878=7452l (1-2 –sisternadagi benzin) 10427-7452=2975l javob: 2975 l benzin 284-misol “porovoz mashqi “ uyga vazifa
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namangan viloyati xtb namangan tuman xtb bo‘limiga qarashli 37-sonli umumiy o’rta ta’lim maktabining boshlang‘ich sinf o‘qituvchisi yuldasheva shahrixonning 4-sinf matematika fanidan “tezlik.vaqt . masofa“ mavzusida tayyorlagan taqdimoti 2019-2020 o‘quv yili propowerpoint.ru dars qoidalari faol bo‘ling diqqat qiling xato qilmang tartib saqlang propowerpoint.ru uyga vazifa: 279-masala 5 ta bir xil qutining massasi 30 kg. 30 ta shunday qutining massasi qancha? 5ta quti 30kg 30ta shunday quti ? kg propowerpoint.ru yechimi: 30:5=6 kg 30·6=180kg javob: 180kg propowerpoint.ru 280-misol 10sr08kg–4sr12kg= 12km750 m + 4 km 075 m= 47 650 – 857 – 6 599= 5 538 – (14 + 778)= yechimi: 10sr08kg–4sr12kg=1008kg-412kg=596kg 12km750 m + 4 km 075 m=12750m-4075m=8675m 47 650 – 857 – 6 599=46793-6599=40194 5 53...

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