4-sinf. matematika. tenglamalar 333

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mavzu: tenglamalar mustaqil topshiriqni tekshirish (43-b). 6-misol. 80 + 630 : 9 · (10 + 990) = 2 700 : (4 + 5) + (240 – 90) = 70 70 000 1 000 70 080 70 080 9 150 300 450 450 mustaqil topshiriqni tekshirish (43-b). 7-masala. masalalarni tenglama tuzib yeching: 1) agar 184 soni noma’lum songa kamaytirilsa,125 hosil bo‘ladi. shu noma’lum sonni toping. 2) agar noma’lum son 184 ga kamaytirilsa, 125 hosil bo‘ladi. shu noma’lum sonni toping. 184 – x = 125 x – 184 = 125 x = 184 - 125 x = 59 184 – 59 = 125 125 = 125 x = 184 + 125 x = 309 309 – 184 = 125 125 = 125 1. 2) tenglamaning yechilishi va tekshirilishini tushuntiring: x + 240 = 360 x = 360 – 240 x = 120 120 + 240 = 360 360 = 360 x + …
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shiriq. tengsizliklar to‘g‘ri bo‘lishi uchun katakchalar o‘rniga qanday raqamlarni qo‘yish mumkin? 6- tenglama (2 000 + x) – 972 = 3 564 (7 002 – x) – 160 = 5 348 1 436 1 4 3 7 37 210 41 620 4 620 900 138 00 804 e’tiboringiz uchun rahmat! image1.jpeg image2.png image3.jpeg image4.jpeg image5.png image6.png image7.jpeg image8.jpeg image9.png image10.jpeg image11.jpeg image12.png image13.jpeg image14.png image15.jpeg
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mavzu: tenglamalar mustaqil topshiriqni tekshirish (43-b). 6-misol. 80 + 630 : 9 · (10 + 990) = 2 700 : (4 + 5) + (240 – 90) = 70 70 000 1 000 70 080 70 080 9 150 300 450 450 mustaqil topshiriqni tekshirish (43-b). 7-masala. masalalarni tenglama tuzib yeching: 1) agar 184 soni noma’lum songa kamaytirilsa,125 hosil bo‘ladi. shu noma’lum sonni toping. 2) agar noma’lum son 184 ga kamaytirilsa, 125 hosil bo‘ladi. shu noma’lum sonni toping. 184 – x = 125 x – 184 = 125 x = 184 - 125 x = 59 184 – 59 = 125 125 = 125 x = 184 + 125 x = 309 309 – 184 = 125 125 = 125 …

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