ratsional kasr

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og’zaki hisob 04.11.2021 uchitel matematiki mbou sosh № 25 g. krimska malaya e.v. algebra 8 sinf ko’phad ko’rinishida ifodalang: (a–5)2 =a2–10a+25 (x+4)2 =x2+8x+16 (3–u)2 =9–6u+u2 (x+2u)2 =x2+4xu+4u2 ko’phadlarni ikkihad yig’indisi kvadrati ko’rinishida ifodalang =(x–8)2 x2–16x+64 =(u+3)2 u2+6u+9 =(3a–b)2 9a2-6ab+b2 =(2x+u)2 4x2+4xu+u2 ko’paytmani hisoblang (a–5)(a+5) =a2–25 (x+4)(x–4) =x2–16 (3b–2)(3b+2) =9b2–4 (5x–1)(5x+1) =25x2–1 ko’phadni ko’paytuvchilarga ajrating =(x–8)(x+8) x2–64 =(5–x)(5+x) 25–x2 =(2b–9)(2b+9) 4b2–81 =(7x–1)(7x+1) 49x2–1 ratsional ifodalar 04.11.2021 uchitel matematiki mbou sosh № 25 g. krimska malaya e.v. algebra 8 sinf algebraik ifoda sonlar va harfardan tuzilib, amallar belgilari bilan birlashtirilgan ifodadir . surat va maxraji algebraic ifodalar bo’lgan kasr algebraik kasr deyiladi algebraik ifodalar: butun ifodalar kasr ifodalar raqamlar, o‘zgaruvchilar, qo‘shish, ayirish va ko‘paytirish amallari, 0dan farqli songa bo‘lish. raqamlar, o'zgaruvchilar, amallar qo'shish, ayirish va ko'paytirish, birhadga, ko'phadga bo'lish ratsional ifodalar misol: 2a – 5x; misol: ratsional kasr deb, bu yerda r va q ko’phadlar; p – algebraik kasrning surati q - …
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iyax peremennoy ne imeet smisla drob: reshenie pri a = - 5 znamenatel obrashaetsya v 0, znachit nedopustimoe znachenie a = -5. otvet: pri a = -5. 14 ustanovite, pri kakix znacheniyax peremennoy ne imeet smisla drob: reshenie - znamenatel (d - 41)(a- 85) = 0, esli d = 41, a = 85. otvet: pri d = 41 ili a = 85. 15 naydite znachenie peremennoy, pri kotorix drob ravna nulyu : ravno 0, esli x - 4 = 0, t.e. pri x = 4; ne mojet bit ravno 0; ravno 0, esli 2x + 6 = 0, t.e. pri x = - 3; ravno 0, esli x + 1 = 0, t.e. pri x = -1. 16 kasrning surati nolga teng bo’lsa, kasr nolga teng. agar kasrning maxraji nolga teng bo’lsa bu kasr ma’noga ega emas yangi mavzuni mustahkamlash ratsional ifoda bo’ladimi?: mojno predstavit kak mnogochlen yavl. algebraicheskoy drobyu …
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mf ) 85 a )( 41 d ( 53 d 99 2 - - - oleobject19.bin oleobject20.bin image36.wmf , 1 x 1 x ) g , 2 x 6 x 2 ) v , x 1 x ) b , 2 x 4 x ) a 2 2 2 + + - + + + - oleobject21.bin image37.wmf - - + - - - - + + - + ; m 12 n 7 n m 3 nm 6 ) g ; t p t 3 ) v ; f 5 f 2 15 f 6 f 2 ) b ; 14 4 a 7 ) a 2 2 2 2 2 2 oleobject22.bin
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og’zaki hisob 04.11.2021 uchitel matematiki mbou sosh № 25 g. krimska malaya e.v. algebra 8 sinf ko’phad ko’rinishida ifodalang: (a–5)2 =a2–10a+25 (x+4)2 =x2+8x+16 (3–u)2 =9–6u+u2 (x+2u)2 =x2+4xu+4u2 ko’phadlarni ikkihad yig’indisi kvadrati ko’rinishida ifodalang =(x–8)2 x2–16x+64 =(u+3)2 u2+6u+9 =(3a–b)2 9a2-6ab+b2 =(2x+u)2 4x2+4xu+u2 ko’paytmani hisoblang (a–5)(a+5) =a2–25 (x+4)(x–4) =x2–16 (3b–2)(3b+2) =9b2–4 (5x–1)(5x+1) =25x2–1 ko’phadni ko’paytuvchilarga ajrating =(x–8)(x+8) x2–64 =(5–x)(5+x) 25–x2 =(2b–9)(2b+9) 4b2–81 =(7x–1)(7x+1) 49x2–1 ratsional ifodalar 04.11.2021 uchitel matematiki mbou sosh № 25 g. krimska malaya e.v. algebra 8 sinf algebraik ifoda sonlar va harfardan tuzilib, amallar belgilari bilan birlashtirilgan ifodadir . surat va maxraji algebraic ifodalar bo’lgan kasr a...

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