organic_chemistry

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organic chemistry the 4th international chemistry olympiad, moscow, 1972 the competition problems from the international chemistry olympiads, volume 1 edited by anton sirota, icho international information centre, bratislava, slovakia 44 problem 5 only one product was obtained by the reaction of bromine with an unknown hydrocarbon. its density was 5,207 times as great as that of the air. problem: 5.1 determine the structural formula of the unknown hydrocarbon. relative atomic masses: ar(h) = 1; ar(c) = 12; ar(br) = 80. ____________________ solution 5.1 relative molecular mass of the initial hydrocarbon can be calculated from the density value: mr(rbr) = 29 × 5.207 = 151 monobromo derivative can only come into consideration because the relative molecular mass of dibromo derivative should be greater: mr(rbr2) > 160 mr(rh) = 151 - 80 + 1 = 72 the corresponding summary formula: c5h12 the given condition (the only product) is fulfilled by 2,2-dimethyl propane: …

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6; ar(k) = 39. ____________________ solution 6.1 stoichiometric formulas of compounds: a : cxhycz 1:1:1 16 17.55 : 1 45.3 : 12 38.41 z:y:x == b : cmhnop 1:3:2 16 22.37 : 1 97.6 : 12 81.55 p:n:m == d : cahboc 20 cm3 of 2 n koh correspond 0.04 / v mol of substance d and it corresponds to 2.68 g of substance d v = 1, 2, 3, ... 1 mol of compound d = v × 67 g 5:6:4 16 70.59 : 1 48,4 : 12 82.35 c:b:a == the 4th international chemistry olympiad, moscow, 1972 the competition problems from the international chemistry olympiads, volume 1 edited by anton sirota, icho international information centre, bratislava, slovakia 46 mr(d) = 67 or 134 or 201, etc. due to both the stoichiometric formula and relative molecular mass of compound d, its composition is c4h6o5. then molecular formulas for compounds …

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2so4 cooh nh2 ch3 hno3 h2so4 kmno4 ch3 cooh fe h2so4 no2 no2 cooh nh2 ch3 the 5th international chemistry olympiad, sofia, 1973 the competition problems from the international chemistry olympiads, volume 1 edited by anton sirota, icho international information centre, bratislava, slovakia 58 problem 6 a gaseous mixture containing two neighbour hydrocarbons of the same homologous series was 14.4 times as dense as hydrogen. this mixture with a volume of 16.8 dm3 was hydrated and 350 g of the solution were obtained when the products of hydration were absorbed in water. ten grams of this solution were taken and heated in the presence of silver(i) oxide which was prepared from 70 cm3 of a 1 n silver(i) nitrate solution. unreacted ag2o was dissolved in an aqueous ammonia solution and a residual precipitate was filtered off. the filtrate was acidified with nitric acid and addition of an excess of sodium …

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nternational information centre, bratislava, slovakia 59 (6) ch3cooh + nh3 → ch3coonh4 (7) [ag(nh3)2]oh + 3 hno3 → agno3 + 2 nh4no3 + h2o (8) ch3coonh4 + hno3 → nh4no3 + ch3cooh (9) nh3 + hno3 → nh4no3 (10) agno3 + nabr → agbr + nano3 (11) ch ≡ ch + 2 h2 → ch3 – ch3 (12) ch3c ≡ ch + 2 h2 → ch3 – ch2 – ch3 6.3 according to (11) and (12) and regarding the excess of hydrogen, amounts of substances before catalytic hydrogenation are as follows: mol25.0.e.i,dm6.5 2 dm2.11 )mixture( 3 3 ==n 26 x + 40 (0.25 – x) = 28.8 × 0.25 x = 0.2 n(c2h2) = 0.2 mol n(c3h4) = 0.05 mol before hydration: 3 3 -1 16.8 dm (mixture) 0.75 mol 22.4 dm mol n = = n(agno3) = c v = 1 mol dm-3 × 0.07 dm3 = 0.070 mol …

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es and a battery containing ten galvanic cells connected in series, each of it having the voltage of 1.5 v and internal resistance of 0.4 ω. the resistance of the voltmeter is 0.5 ω and the polarisation voltage of the battery is 1.5 v. electric current flows for 8 hours, 56 minutes and 7 seconds through the electrolyte. hydrogen obtained in this way was used for a synthesis with another substance, thus forming a gaseous substance a which can be converted by oxidation with oxygen via oxide to substance b. by means of substance b it is possible to prepare substance c from which after reduction by hydrogen substance d can be obtained. substance d reacts at 180 °c with a concentration solution of sulphuric acid to produce sulphanilic acid. by diazotization and successive copulation with p-n,n-dimethylaniline, an azo dye, methyl orange is formed. problems: 1. write chemical equations for …

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organic chemistry the 4th international chemistry olympiad, moscow, 1972 the competition problems from the international chemistry olympiads, volume 1 edited by anton sirota, icho international information centre, bratislava, slovakia 44 problem 5 only one product was obtained by the reaction of bromine with an unknown hydrocarbon. its density was 5,207 times as great as that of the air. problem: 5.1 determine the structural formula of the unknown hydrocarbon. relative atomic masses: ar(h) = 1; ar(c) = 12; ar(br) = 80. ____________________ solution 5.1 relative molecular mass of the initial hydrocarbon can be calculated from the density value: mr(rbr) = 29 × 5.207 = 151 monobromo derivative can only come into consideration because the relative molecular mass of dibromo derivative should …

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