eruvchanlik yechim 2020

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“vodiy-ziyo” o’quv markazi. rasulov muslimbek eruvchanlika oid birinchi darajali testlar. 1. 40 co haroratdagi 20% li naoh ning eruvchanligi toping. a) 120 b) 30 c) 20 d) 25 yechim; 80% suv ........20% tuz ..............100% eritma 100 gr ……..a=25 eruvchanlik. javob; 25 d). 2. 30 co haroratdagi 15% li naoh ning eruvchanligi toping. a) 17,64 b) 30 c) 20 d) 25 3. 45 co haroratdagi 25% li naoh ning eruvchanligi toping. a) 120 b) 33,3 c) 20 d) 25 4. 50 co haroratdagi 24% li koh ning eruvchanligi toping. a) 120 b) 33,3 c) 31,6 d) 25 5. 10 co haroratdagi 40% li h2so4 ning eruvchanligi toping. a) 66,6 b) 33,3 c) 20 d) 25 6. 25 co haroratdagi 28% li nacl ning eruvchanligi toping. a) 128 b) 33,3 c) 20 d) 38,9 7. 15 co haroratdagi 28,57% li ca(oh)2 ning eruvchanligi toping. a) 120 b) 40 c) 20 d) 38,9 …

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a 90 g tuz 150 g suvda ertilib to’yingan eritma hosil qilingan. shu tuzning 25 co haroratdagi eruvchanligini toping. a) 60 b) 30 c) 45 d) 55 17. 40 co haroratda 75 g tuz 250 g suvda ertilib to’yingan eritma hosil qilingan. shu tuzning 40 co haroratdagi eruvchanligini toping. a) 120 b) 30 c) 20 d) 25 18. 35 co haroratda 78 g tuz 380 g suvda ertilib to’yingan eritma hosil qilingan. shu tuzning 35 co haroratdagi eruvchanligini toping. a) 120,2 b) 33,3 c) 25,31 d) 20,5 19. 25 co haroratda 16 g tuz 40 g suvda ertilib to’yingan eritma hosil qilingan. shu tuzning 25 co haroratdagi eruvchanligini toping. a) 140 b) 33,3 c) 40 d) 38,9 20. 32 co haroratda 96 g tuz 300 g suvda ertilib to’yingan eritma hosil qilingan. shu tuzning 32 co haroratdagi eruvchanligini toping. a) 120,2 b) 32 c) 25,31 d) 38,9 21. ma’lum bir …

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’lum bir haroratda 2,5 mol koh 15 mol suvda to’liq eritildi. ishqorning shu haroratdagi eruvchanligini toping. a) 100 b) 50 c) 51,85 d) 80 29. ma’lum bir haroratda 4,5 mol nacl 18 mol suvda to’liq eritildi. tuzning shu haroratdagi eruvchanligini toping. a) 81,25 b) 50 c) 25 d) 80 30. ma’lum bir haroratda 6 mol nacl 20 mol suvda to’liq eritildi. tuzning shu haroratdagi eruvchanligini toping. a) 112 b) 60 c) 97,5 d) 90 31. ma’lum bir haroratda nano3 tuzining eruvchanlik koffisienti 40 ga teng. shu tuzning c% toping. a) 40 b) 28,57 c) 25 d) 80 yechim; 100 suv………….40 tuz………………140 to’yingan eritma a=28.57 %................100% javob; 28.57 % b). 32. ma’lum bir haroratda na2so4 tuzining eruvchanlik koffisienti 25 ga teng. shu tuzning c% toping. a) 25 b) 50 c) 20 d) 80 33. ma’lum bir haroratda nacl tuzining eruvchanlik koffisienti 35,6 ga teng. shu tuzning c% toping. a) 25 b) …

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20………………b= 120 javob; eruvchanlik = 20 c). 42. ma’lum bir haroratda molyalligi 7 ga teng bo’lgan naoh ning eruvchanligini toping. a) 28 b) 50 c) 20 d) 80 43. ma’lum bir haroratda molyalligi 3,5 ga teng bo’lgan koh ning eruvchanligini toping. a) 24,5 b) 39,2 c) 20 d) 80 44. ma’lum bir haroratda molyalligi 2 ga teng bo’lgan cuso4 ning eruvchanligini toping. a) 24,5 b) 50 c) 20 d) 32 45. ma’lum bir haroratda molyalligi 2,75 ga teng bo’lgan cuso4 ning eruvchanligini toping. a) 24,5 b) 44 c) 20 d) 80 46. ma’lum bir haroratda molyalligi 3 ga teng bo’lgan k2so4 ning eruvchanligini toping. a) 52,2 b) 50 c) 20 d) 80 47. ma’lum bir haroratda molyalligi 2,25 ga teng bo’lgan k2so4 ning eruvchanligini toping. a) 24,5 b) 39,15 c) 20 d) 80 48. ma’lum bir haroratda molyalligi 6 ga teng bo’lgan nano3 ning eruvchanligini toping. a) 24,5 b) 51 …

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2so4 ning 25 oc dagi eruvchanligi 25 ga teng. shu haroratdagi k2so4 ning 160 5% eritmasini to’yintirish uchun eritmaga necha gramm tuz qo’shish kerak. a) 24 b) 80 c) 30 d) 40 56. k2so4 ning 35 oc dagi eruvchanligi 45 ga teng. shu haroratdagi k2so4 ning 200 25% eritmasini to’yintirish uchun eritmaga necha gramm tuz qo’shish kerak. a) 24 b) 17,5 c) 30 d) 40 57. cuso4 ning 30 oc dagi eruvchanligi 48 ga teng. shu haroratdagi cuso4 ning 70 16% eritmasini to’yintirish uchun eritmaga necha gramm tuz qo’shish kerak. a) 24 b) 80 c) 30 d) 17 58. cuso4 ning 20 oc dagi eruvchanligi 50 ga teng. shu haroratdagi cuso4 ning 800 30% eritmasini to’yintirish uchun eritmaga necha gramm tuz qo’shish kerak. a) 24 b) 80 c) 30 d) 40 59. caso4 ning 25 oc dagi eruvchanligi 54 ga teng. shu haroratdagi caso4 ning 600 28% eritmasini to’yintirish uchun …

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“vodiy-ziyo” o’quv markazi. rasulov muslimbek eruvchanlika oid birinchi darajali testlar. 1. 40 co haroratdagi 20% li naoh ning eruvchanligi toping. a) 120 b) 30 c) 20 d) 25 yechim; 80% suv ........20% tuz ..............100% eritma 100 gr ……..a=25 eruvchanlik. javob; 25 d). 2. 30 co haroratdagi 15% li naoh ning eruvchanligi toping. a) 17,64 b) 30 c) 20 d) 25 3. 45 co haroratdagi 25% li naoh ning eruvchanligi toping. a) 120 b) 33,3 c) 20 d) 25 4. 50 co haroratdagi 24% li koh ning eruvchanligi toping. a) 120 b) 33,3 c) 31,6 d) 25 5. 10 co haroratdagi 40% li h2so4 ning eruvchanligi toping. a) 66,6 b) 33,3 c) 20 d) 25 6. 25 co haroratdagi 28% li …

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