9. reaksiyali masalalar - 3 (2023)

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reaksiyali masalalar – 3 sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 𝐾2𝑂 + 𝐻2𝑂 → 2𝐾𝑂𝐻 336 + 36 = 372g(𝐻2𝑂) sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 1. kaliy oksidi ma’lum massadagi suvda to‘liq eritildi. olingan asos massasi eritilgan oksid massasidan 36 g ga ko‘p bo‘lsa, necha gramm 40 % li eritma hosil bo‘lgan? a) 420 b) 480 c) 540 d) 560 94g ___ 18g____ 112g _____ ∆ = 112 – 94 = 18g 18g 36g____x x = 224g ____x x = 36g ____x x = 188g 224g _____ 40% 100%____x x = 560g → eritma 224g _____ 40% 60%____x x = 336g nah + 𝐻2𝑂 → 𝑁𝑎𝑂𝐻 + 𝐻2 440 + 27 = 467g(𝐻2𝑂) sardor voxidov//@kimyosvssardor voxidov//@kimyosvs natriy gidrid ma’lum massadagi suvda to‘liq eritildi. olingan asos massasi eritilgan gidrid massasidan 24 g ga ko‘p bo‘lsa, necha gramm 12 % li eritma hosil bo’lgan. a) 500 b) 480 c) 540 d) 560 24g ___ 18g____ 40g _____ …

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voxidov//@kimyosvssardor voxidov//@kimyosvs 7. kalsiy xlorid eritmasiga tegishli miqdorda na2co3 qo‘shilganda 100 g cho‘kma tushdi va 4 molyalli eritma hosil bo‘ldi. dastlabki kalsiy xlorid eritmasining massasini (g) aniqlang. a) 617 b) 500 c) 622 d) 611 111g ____ 106g ______100g ____ 2mol 100g111g ____ 106g ______ ____ x = 2mol 4mol _____1000g 2mol ____ x = 500g𝐶𝑎𝐶𝑙2 111g + 𝐻2𝑂 + 500g = 611g dastlabki eritma: 𝐵𝑎𝐶𝑙2 + 𝑁𝑎2𝑆𝑂4 → 𝐵𝑎𝑆𝑂4 + 2𝑁𝑎𝐶𝑙 nacl sardor voxidov//@kimyosvssardor voxidov//@kimyosvs bariy xlorid eritmasiga tegishli miqdorda na2so4 qo‘shilganda 69,9 g cho‘kma tushdi va 2,5 molyalli eritma hosil bo‘ldi. dastlabki bariy xlorid eritmasining massasini (g) aniqlang. a) 302,4 b) 289,6 c) 240 d) 611 208g ____ 142g ______233g ____ 2mol 69,9g62,4g ____ 42,6g______ ____ x = 0,6mol 2,5mol_____1000g 0,6mol____ x = 240g𝐵𝑎𝐶𝑙2 62,4g + 𝐻2𝑂 + 240g = 302,4g 2𝐴𝑔𝑁𝑂3 + 𝐶𝑎𝐶𝑙2 → 2𝐴𝑔𝐶𝑙 + 𝐶𝑎(𝑁𝑂3)2 ______ 1 litr − x 𝐶𝑎𝐶𝑙2 + 11. kumush nitrat …

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mdagi kalsiy xlorid eritmasi qo‘shildi. hosil bo‘lgan eritmada kumush va nitrat ionlari 1:5 mol nisbatda bo‘lsa, dastlabki eritmalarning molar konsentratsiyalari qanday nisbatda (berilgan tartibda) bo‘lgan? a) 1:5 b) 5:1 c) 5:6 d) 5:3 𝐴𝑔𝑁𝑂3 𝐶𝑎𝐶𝑙2 𝐶𝑎(𝑁𝑂3)2 2 litr 3 litr − y 2x + y = 5(no3) y = 1 (ag) y = 1 x = 2 2mol_____4mol____2mol_____4m 4+1m_____ 1 litr =5m = 2mol________ 2 litr =1m 5m: 1m → 5:1 naoh _______ sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 14. 40 g 30 % li natriy gidroksid eritmasida qanday massadagi (g) fosfat angidrid eritilganda ekvimolar nisbatdagi nordon tuzlar aralashmasi hosil bo‘ladi? a) 56,8 b) 14,2 c) 28,4 d) 42,6 40g ∙ 0,3= 12g_____ 40g = 0,3mol naoh + 𝑃2𝑂5 → 𝑁𝑎𝐻2𝑃𝑂4 + 𝑁𝑎2𝐻𝑃𝑂43 3mol ____ 142g 0,3mol ____ x = 14,2g naoh _______ sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 200 g 28 % li natriy gidroksid eritmasida qanday massadagi (g) fosfat angidrid eritilganda 1:3 mol ( …

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ortofosfat kislotaning suvli eritmasiga 180 ml 5m li ammiak eritmasi qo‘shildi. natijada konsentratsiyasi 2 mol/l bo‘lgan eritma olindi. hosil bo‘lgan eritma hajmini (ml) aniqlang. a) 250 b) 275 c) 225 d) 200 44,1g______ 98g = 0,45mol 𝑁𝐻3 1000ml ____ 5mol 180ml ___ x x = 0,9mol 1 : 2 2𝑁𝐻3 + 𝐻3𝑃𝑂4 → (𝑁𝐻4)2𝐻𝑃𝑂4 2m ____1m ______1m 0,45m _____ x = 1000ml ______2m 0,45m_____ x x = 225ml 𝐻3𝑃𝑂4 = 0,5mol sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 49 g ortofosfat kislotaning suvli eritmasiga 250 ml 6m li ammiak eritmasi qo‘shildi. natijada konsentratsiyasi 2,5 mol/l bo‘lgan eritma olindi. hosil bo‘lgan eritma hajmini (ml) aniqlang. a) 250 b) 275 c) 225 d) 200 49g______ 98g = 0,5mol 𝑁𝐻3 1000ml ____ 6mol 250ml ___ x x = 1,5mol 1 : 3 3𝑁𝐻3 + 𝐻3𝑃𝑂4 → (𝑁𝐻4)3𝑃𝑂4 2m ____1m ______1m 0,5m _____ x = 1000ml ______2,5m 0,5m_____ x x = 200ml ______ sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 25. 32,1 …

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ml agno3 (c = 0,4 mol/l) va 750 ml nacl (c = 0,1 mol/l) eritmalari aralashtirildi. eritmadan cho‘kma ajratib olingach, barcha ionlar konsentratsiyasini (mol/l) hisoblang. 1) ag+; 2) n𝑂3 −; 3) na+; 4) c𝑙−, a) 0,02; b) 0,075; c) 0,025; d) 0,1 a) 3-c; 4-b; 2-b b) 3-c; 4-d; 2-b c) 3-c; 2-b; 1-b d) 3-b; 2-d; 1-c _____ 𝐴𝑔𝑁𝑂3 sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 31. 0,7 mol natriy bromid va kalsiy bromid aralashmasidagi bromid ionlarini to‘liq cho‘ktirish uchun 670 g 2 molyalli agno3 eritmasi sarflandi. boshlang‘ich aralashmadagi natriy bromid massasini (g) hisoblang. (molyal konsentratsiya – 1 kg erituvchiga to‘g‘ri keladigan erigan moddaning mol miqdori.) a) 41,2 b) 30,9 c) 51,5 d) 20,6 x----------x-------------x------------x 1000g____ 340g _____1340g _____ 2mol 670g x = 1mol nabr + 𝐴𝑔𝑁𝑂3 → 𝑁𝑎𝑁𝑂3 + 𝐴𝑔𝐵𝑟 ca𝐵𝑟2 + 2𝐴𝑔𝑁𝑂3 → 𝐶𝑎(𝑁𝑂3)2 + 2𝐴𝑔𝐵𝑟 y -------- 2y -----------y-------------2y 0,7m 1m x + y = 0,7 x + 2y = …

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reaksiyali masalalar – 3 sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 𝐾2𝑂 + 𝐻2𝑂 → 2𝐾𝑂𝐻 336 + 36 = 372g(𝐻2𝑂) sardor voxidov//@kimyosvssardor voxidov//@kimyosvs 1. kaliy oksidi ma’lum massadagi suvda to‘liq eritildi. olingan asos massasi eritilgan oksid massasidan 36 g ga ko‘p bo‘lsa, necha gramm 40 % li eritma hosil bo‘lgan? a) 420 b) 480 c) 540 d) 560 94g ___ 18g____ 112g _____ ∆ = 112 – 94 = 18g 18g 36g____x x = 224g ____x x = 36g ____x x = 188g 224g _____ 40% 100%____x x = 560g → eritma 224g _____ 40% 60%____x x = 336g nah + 𝐻2𝑂 → 𝑁𝑎𝑂𝐻 + 𝐻2 440 + 27 = 467g(𝐻2𝑂) sardor voxidov//@kimyosvssardor voxidov//@kimyosvs natriy gidrid ma’lum massadagi suvda to‘liq eritildi. olingan asos …

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