xarakteristik funksiyalar

DOC 332.5 KB Free download

Page preview (5 pages)

Scroll down 👇

1576504206.doc x it e x x j it me x = ) ( ) ( x f x ) ( ) ( x df itx е x ò ¥ ¥ - = x j x ) ( x p dx x p itx е x ) ( ) ( ò ¥ ¥ - = x j ) ( x p x k n k itx p e t k å = = 1 ) ( x j 1 ) ( £ = x x j it me t x 1 ) 0 ( = x j t 1 ) ( £ t x j = ) 0 ( x j ) ( x df iox е ò ¥ ¥ - ò = -¥ - +¥ = ¥ ¥ - 1 ) ( ) ( ) ( f f x df . 1 ) ( ) ( ) ( ) ( …

ò ò ò ò - ¥ - + - - + + - ¥ + + + + + = d d d d d d d d y 1 1 1 2 1 2 2 2 ) ( ) , , , ( 2 1 x x x x x x x x с z df x x z c j dt t x t t x z t x x z c c c ò - ú û ù ê ë é - - - = ) sin( ) ( sin 1 ) , , , ( 1 2 1 p y 0 > d d d - < + 2 1 x x , 0 ® d ¥ ® c ) ( x f ò - - ¥ ® -¥ ® - = c c izx ity e y dt t d it e e x f …

uzluksiz. isboti: oldin berilgan uchun, a ni shunday tanlaymizki, so`ngra ni shunday tanlaymizki, bo`lsin, natijada bo`ladi. 5o. bu yerda , ning kompleks qo`shmasi. bu xossaning isboti tenglikdan kelib chiqadi. quyidagi poya teoremasini isbotisiz keltiramiz. 6o . poya teoremasi, ,( ) quyidagi shartlarni qanoatlantiruvchi funksiya bo`lsin: a) (0, (0)=1, va t(( da (t)(0. b) funksiya uzluksiz, juft va botiq. bundan funksiya biror taqsimot funksiyaning xarakteristik funksiyasi bo`ladi. 1- teorema. agar ( tasodifiy miqdor n-tartibli absolyut momentga ega bo`lsa, xarakteristik funksiya n marta diffyerenstiallanuvchi va k( n uchun (2) va embed equation.3 (3) bu yerda t(0 da va barcha t lar uchun isboti: xarakteristik funksiyasi k marta formal diffyerenstiallash quyidagiga olib keladi: (4) bo`lganligi uchun teorema shartidan (4) integralning mavjudligi va differensiallashning qonuniyligi kelib chiqadi. (4) da deb olsak kelib chiqadi. (3) ni isbotlash uchun teylor formulasidan foydalanamiz. ma`lumki, shuning uchun bu yerda va - tasodifiy miqdorlar va . (3) ga ega …

siyasi topilsin. ma`lumki, tasodifiy miqdorning xaraktyerischtik funksiyasi xarakteristik funksiya logarifmi hosilasi yordamida matematik kutilma va dispyersiyani ifodalash mumkin. deb olamiz. va ekanligini hisobga olsak, va demak, va . xarakteristik funksiya logarifmining tartibli hosilasining nol nuqtadagi qiymatining ga ko`paytirilganiga tasodifiy miqdorning tartibli ettiinvarianti deyiladi. tasodifiy miqdorning taqsimot funksiyasini bilgan holda uning xarakteristik funksiyasini topish mumkinligini bilamiz. teskari tadqiq ham o`rinli. 2 – teorema. agar va lar mos ravishda tasodifiy miqdorning xarakteristik va taqsimot funksiyalari bo`lsalar, hamda va lar taqsimot funksiyaning uzluksizlik nuqtalari bo`lsalar, u holda (5) o`rinli bo`ladi. teoremani isbotlash sxemasini keltiramiz. xarakteristik funksiya ta`rifi va kompleks o`zgaruvchining funksiyalari nazariyasidan olgan bilimlarimiz asosida (6) ga ega bo`lamiz. matematik analiz kursidan ma`lumki (7) deb olib integralni (8) ko`rinishda yozib olamiz, bu yerda va , . da limitiga o`tib, (7) va taqsimot funksiyaning xossalaridan foydalanib, teorema isbotiga ega bo`lamiz. (5) formulaga teskarilash formulasi deyiladi. bu formuladan quyidagi yagonalik teoremasi kelib chiqadi. 3- teorema. …

ristik funksiyalar ketma-ketligi uzluksiz bo`lgan biror funksiyaga intilsa, bu xarakyeristik funksiyalarga mos taqsimot funksiyalar ketma- ketligi taqsimot funksiyaga sust yaqinlashadi va bo`ladi. _1305269520.unknown _1305270827.unknown _1306253384.unknown _1306253863.unknown _1306253959.unknown _1306257053.unknown _1307908125.unknown _1307908247.unknown _1307908289.unknown _1307908135.unknown _1306257232.unknown _1306257272.unknown _1306257193.unknown _1306257213.unknown _1306257111.unknown _1306253995.unknown _1306256932.unknown _1306253978.unknown _1306253920.unknown _1306253944.unknown _1306253908.unknown _1306253779.unknown _1306253846.unknown _1306253858.unknown _1306253841.unknown _1306253596.unknown _1306253731.unknown _1306253461.unknown _1305271877.unknown _1305272542.unknown _1305272635.unknown _1305272782.unknown _1305272887.unknown _1306253376.unknown _1305272903.unknown _1305272877.unknown _1305272745.unknown _1305272592.unknown _1305272606.unknown _1305272564.unknown _1305272218.unknown _1305272473.unknown _1305272488.unknown _1305272412.unknown _1305271973.unknown _1305271983.unknown _1305271959.unknown _1305271619.unknown _1305271748.unknown _1305271852.unknown _1305271733.unknown _1305271577.unknown _1305271590.unknown _1305270836.unknown _1305270941.unknown _1305270189.unknown _1305270447.unknown _1305270662.unknown _1305270802.unknown _1305270814.unknown _1305270721.unknown _1305270455.unknown _1305270415.unknown _1305270437.unknown _1305270245.unknown _1305269853.unknown _1305270049.unknown _1305270112.unknown _1305269995.unknown _1305269601.unknown _1305269832.unknown _1305269593.unknown _1272284997.unknown _1272287562.unknown _1305269458.unknown _1305269468.unknown _1272287622.unknown _1290102729.unknown _1290102800.unknown _1290102971.unknown _1290103004.unknown _1305269381.unknown _1290102990.unknown _1290102867.unknown _1290102762.unknown _1272287893.unknown _1272347220.unknown _1290102712.unknown _1272350934.unknown _1272287681.unknown _12

Want to read more?

Download the full file for free via Telegram.

Download full file

About "xarakteristik funksiyalar"

1576504206.doc x it e x x j it me x = ) ( ) ( x f x ) ( ) ( x df itx е x ò ¥ ¥ - = x j x ) ( x p dx x p itx е x ) ( ) ( ò ¥ ¥ - = x j ) ( x p x k n k itx p e t k å = = 1 ) ( x j 1 ) ( £ = x x j it me t x 1 ) 0 ( = x j t 1 ) ( £ t x j = ) 0 ( x j ) ( x df iox е ò ¥ ¥ - …

DOC format, 332.5 KB. To download "xarakteristik funksiyalar", click the Telegram button on the left.

Tags: xarakteristik funksiyalar DOC Free download Telegram