grinformulasi

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Updated Dec 2025

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prezentatsiya powerpoint grin formulasi bajardi: geldiyev jahongir, jonizoqov husniddin grin formulasi nazorat savollari 1. grin formulasi nimani ifodalaydi? 2. grin formulasini keltirib chiіarishda іanday yo’l tutilgan? 3. јanday shart bajarilganda , yopiі kontur bo’yicha olingan egri chiziіli integral nolga teng? 4. teoremani isbotlashda іanday usuldan foydalanilgan? 5. tekis figuraning yuzini hisoblash formulasini keltirib chiіarishda nimalardan foydalanilgan? 6.misollar yechish. etiboringiz uchun rahmat image2.jpg image3.png image4.jpeg image5.png image6.png image7.png image8.png image9.png image10.gif grin formulasi. bu formula kvadratlanuvehi d soha bodyicha olingan ikki omichovli integral bilan, shu d sohaning konturi bodigan l chiziq bouylab olingan egri chiziqli integral orasidagi bogulanishni ifodalaydi. r(x) va q(xu) funktsiyalar d sohaning ichki nugtalarida va d ning konturi l ning @p nuqtalarida aniqlangan, uzluksiz va uzluksiz ee xususiy xosilalarga ega bollsin. (l- qismiy silliq bo lish ham mumkin) u holda quyidagi grin formulasi odrinli bodladi. §e-$ saxay =] povae +ox.y)dr (1) bundan keyin j belgi _l-yopiq kontur bo’yicha …

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l yoki gorizontal chiziqlar ikkitadan kolproq nuqtalarda kesib outadigan bolisa, uni ikkita d; va dz sobalarga ajratamiz (masalan rasmdagidek av kesma bilan) va har bir d; va ds larga grin formulasini alohida qoullaymiz | pae+ ody bulami ikkalasini gocshsak, yana grin formulasiga ega bodilamiz, chunki [ va [ odzaro eo yougolib ketadi. agar d soha ikkita ly va l2 konturlar bilan chegaralangan bouilsa (rasmdagidek) ham grin formulasi ourinli bo oladi| agar d soha ikkita l, va l; konturlar bilan chegaralangan bolilsa (rasmdagidek) ham grin formulasi ourinli bodladi. bu holdad sohani yagona av+li+ va4l> kontur bilan chegaralangan deb qarash mumkin, [ pe.y)ae+ ogay)dy jexdy = [pex+qdy grin formulasi d soha bollyicha olingan ikki odichovli integral d ning konturi bolyicha olingan egri chiziqli integralga teng bouladi. faqat harakat younalishi tashqi konturda musbat (soat strelkasi younalishiga qarshi) ichki konturda soat strelkasi younalishida bolladi. tekis figuraning yuzini hisoblash. yopiq, qisman silliq l kontur bilan …

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alga teng bolladi. boshgacha aytganda, egri chiziqli integral integrallash youliga emas, fagat m va n_ nugtalarning ‘olmiga bogiliq bouladi? shu savolga javob izlaymiz. shartga kora [paco | pa = ody @ « aes) =0, [pak ody~ (lpe ody =0, aks bunday xulosaga keldik: agar egri chizigl integral integrallash youliga bogdlliq ‘boliimasa, ixtiyoriy yopiq kontur bollyicha olingan integral nolga teng bolllar ekan. kolirinib turibdiki, teskari dahvo ham olrinli. yugorida qocyilgan savolga quyidagi teorema javob beradi. teorema. kvadratlanuvchi d sohaning barcha nugtalarida r(x,u) va q(x.u) funktsiyalar oozlarining 4 2 xususiy hosilalari bilan uzluksiz bollsin. [ pax + qdy integral shu d sohada todlliq yotuvchi ixtiyoriy yopig, qisman silliq l kontur boclyicha nolga teng bocllishi uchun d sohaning barcha nugtalarida 4 bbotlishi zarur va yetarlidir. a isbot. yetarliligi. grin formulasidan bevosita kelib chigadi, chunki tenglikning chap qe =0 tomonidagi integral ostidagi ifoda =.= & @ c20 bodladigan s soni mayjud, z 4 funktsiya, …

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prezentatsiya powerpoint grin formulasi bajardi: geldiyev jahongir, jonizoqov husniddin grin formulasi nazorat savollari 1. grin formulasi nimani ifodalaydi? 2. grin formulasini keltirib chiіarishda іanday yo’l tutilgan? 3. јanday shart bajarilganda , yopiі kontur bo’yicha olingan egri chiziіli integral nolga teng? 4. teoremani isbotlashda іanday usuldan foydalanilgan? 5. tekis figuraning yuzini hisoblash formulasini keltirib chiіarishda nimalardan foydalanilgan? 6.misollar yechish. etiboringiz uchun rahmat image2.jpg image3.png image4.jpeg image5.png image6.png image7.png image8.png image9.png image10.gif grin formulasi. bu formula kvadratlanuvehi d soha bodyicha olingan ikki omichovli integral bilan, shu d sohaning konturi bodigan l chiziq bouylab olingan egri chiziqli integral orasidagi...

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