matematik masalalarni dasturlash c++ tili yordamida yechish

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matematik masalalarni dasturlash c++ tili yordamida yechish oxirgi raqam natural son berilgan, uning oxirgi raqamini chop eting . #include std nom maydonidan foydalanish ; int main() { int n; cin >> n; cout std nom maydonidan foydalanish ; int main() { int n; cin >> n; cout std nom maydonidan foydalanish ; int main() { int n; cin >> n; cout std nom maydonidan foydalanish ; int main() { int n; cin >> n; int e = n%10; int w = (n%100 - n%10)/10; int q = (((n%1000) - (n%100) )/100); cout std nom maydonidan foydalanish ; int main() { int n; cin >>n; cout std nom maydonidan foydalanish ; int main() { int a; cin >> a; int z =a/1000; int n = a% 1000; int x = n/100; int m = n%100; int c = m/10; int v = m%10; int zo = z*10+x+1; int zyz = v*10+c+1; …

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tacha = c; min= a; } } cout std nom maydonidan foydalanish ; int main() { int a, b, c ; cin >>a; b=1; esa (c a){ sindirish ; } cout std nom maydonidan foydalanish ; int main() { int a, b ; a=2; cin >>b; agar (b==1){ a=1; } esa (a #o'z ichiga std nom maydonidan foydalanish ; int main() { int a, b, c ; cin >>a; c=0; b=2; while ( pow ( b,c ) #o'z ichiga std nom maydonidan foydalanish ; int main() { int a, b, c ; cin >>a; b=2; c=0; esa (c foydalanish nom maydoni std ; int main() { int a, b ; b=0; cin >>a; esa (a!=0){ b ++; cin >>a; } cout std nom maydonidan foydalanish ; int main() { int a, b ; cin >>a; b=0; esa (a!=0){ b+=a; cin >>a; } cout foydalanish nom maydoni std ; int main() …

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oydalanish ; int main() { ikki barobar a, b ; cin >> a; b=a- trunk ( a); cout #o'z ichiga std nom maydonidan foydalanish ; int main() { juft b; cin >>b; cout #o'z ichiga std nom maydonidan foydalanish ; int main() { ikki barobar a,b,c,p ; cin >>a>>b>>c; p =( a+b+c )/2; cout #o'z ichiga std nom maydonidan foydalanish ; int main() { ikki barobar p,a,b,c,s ; cin >>p>>a>>b; p=p/100; c =( a*100)+b; s=c*p; int l= trunc ( c+s ); b=l%100; a=l/100; cout std nom maydonidan foydalanish ; int main() { ikki barobar a, b, c ; cout.precision ( 11); c=0; b=0; cin >>a; while( a!=0){ b= b+a ; c ++ ; cin >>a; } cout #o'z ichiga std nom maydonidan foydalanish ; int main() { ikki barobar a,b,c,n,i ; cin >>a; b=0; c=0; n=0; esa (a!=0){ b=b +( a*a); c= c+a ; n ++; cin >>a; } cout.precision …

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matematik masalalarni dasturlash c++ tili yordamida yechish oxirgi raqam natural son berilgan, uning oxirgi raqamini chop eting . #include std nom maydonidan foydalanish ; int main() { int n; cin >> n; cout std nom maydonidan foydalanish ; int main() { int n; cin >> n; cout std nom maydonidan foydalanish ; int main() { int n; cin >> n; cout std nom maydonidan foydalanish ; int main() { int n; cin >> n; int e = n%10; int w = (n%100 - n%10)/10; int q = (((n%1000) - (n%100) )/100); cout std nom maydonidan foydalanish ; int main() { int n; cin >>n; cout std nom maydonidan foydalanish ; int main() { int a; cin >> a; int z …

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