mock 1 matematika

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sayxun team azizbek nuraliyev guliston academy sanjar rahimjonov t/mesayxunteamlc +99891 020 03 06 mock 1 matematika [1,3 ball] 1. ๐‘Ž + ๐‘ + ๐‘ = 25 boโ€™lsa, 50 โˆ’ 2๐‘Ž โˆ’ 2(๐‘ + ๐‘) ning qiymatini toping. a) 2 b) 3 c) 0 d) 1 [2,2 ball] 2. hisoblang: 0,0(6) 0,06 + 0,0(8) 0,08 + 10 9 a) 28 9 b) 10 3 c) 11 3 d) 25 9 [1,3 ball] 3. ๐‘Ž va ๐‘ natural sonlar uchun 2๐‘Ž โˆ™ 3๐‘ = 72 boโ€™lsa, ๐‘Ž + ๐‘ ni qiymatini toping. a) 3 b) 4 c) 5 d) 6 [2,2 ball] 4. yigโ€™ilgan 1 t mevaning 82% i suvdan iborat. maโ€™lum vaqtdan keyin bu mevadagi suvning miqdori 70% ga tushdi. endi bu mevaning ogโ€™irligi necha kg chiqadi? a) 600 b) 580 c) 610 d) 590 [1,3 ball] 5. soddalashtiring: (๐‘Žโˆ’2 + ๐‘โˆ’3)(๐‘Žโˆ’2 โˆ’ ๐‘โˆ’3) a) ๐‘Žโˆ’4 + ๐‘โˆ’6 b) ๐‘Žโˆ’4 โˆ’ โ€ฆ
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cos3๐‘ฅ + 1 cos3๐‘ฅโˆ™cos 5๐‘ฅ + โ‹ฏ + 1 cos2023๐‘ฅโˆ™cos2025๐‘ฅ a) tg 2024๐‘ฅ sin 2๐‘ฅ b) tg 2025๐‘ฅโˆ’tg๐‘ฅ sin 2๐‘ฅ c) tg 2025๐‘ฅโˆ’tg๐‘ฅ sin ๐‘ฅ d) tg 2025๐‘ฅ sin 2๐‘ฅ [1,3 ball] 16. tg 25ยฐ = ๐‘Ž boโ€™lsa, cos 40ยฐ ni ๐‘Ž orqali ifodalang. a) 1โˆ’๐‘Ž2 1+๐‘Ž2 b) 2๐‘Ž 1โˆ’๐‘Ž2 c) 1+๐‘Ž2 1โˆ’๐‘Ž2 d) 2๐‘Ž 1+๐‘Ž2 sayxun team azizbek nuraliyev guliston academy sanjar rahimjonov t/mesayxunteamlc +99891 020 03 06 [1,3 ball] 17. ๐‘ฆ = |๐‘ฅ2 โˆ’ 2๐‘ฅ โˆ’ 5| funksiyaning ๐‘ฅ = 4 nuqtadagi hosilasini toping. a) 6 b) โ€“6 c) 0 d) 3 [2,2 ball] 18. ๐‘“(๐‘ฅ + 3) = 2๐‘“(๐‘ฅ) + 5 va ๐‘“(2) = 4 boโ€™lsa, ๐‘“(8) ni toping. a) 25 b) 26 c) 28 d) 31 [2,2 ball] 19. |๐‘ฅ โˆ’ 4|๐‘ฅ2โˆ’3๐‘ฅ+ 3 2 = 1 tenglama nechta ildizga ega? a) 1 ta b) 3 ta c) 4 ta d) 5 ta [2,2 ball] 20. (โˆš5 โ€ฆ
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b) 36 c) 12 d) 24 [2,2 ball] 29. toโ€™gโ€™ri burchakli parallelepipedning asonini tomonlari 12 va 16 ga teng. parallelepiped diagonali uzunligi 25 boโ€™lsa, uning diagonal kesim yuzini toping. a) 250 b) 300 c) 240 d) 320 [2,2 ball] 30. ๐ด toโ€™plam elementlari 48 ning, ๐ต toโ€™plam elementlari 60 ning natural boโ€™luvchilari. ๐ด โˆฉ b ning elementlar sonini toping. a) 6 b) 8 c) 12 d) 9 [2,2 ball] 31. qutida 8 ta oq va 7 ta qora shar bor. qutidan 2 ta shar tanlab olindi. tanlangan sharlarning barchasi qora boโ€™lishi ehtimolini toping. a) 1 8 b) 1 5 c) 7 15 d) 7 30 sayxun team azizbek nuraliyev guliston academy sanjar rahimjonov t/mesayxunteamlc +99891 020 03 06 [2,2 ball] 32. chizmadagi uchburchaklar sonini toping. a) 40 b) 55 c) 60 d) 70 topshiriqlar (33-35) va javob variantlari (a-f) ni oโ€™zaro moslashtiring. funksiya grafigidan foydilanib quyidagilarni [โˆ’3; 7] oraliqda yeching โ€ฆ
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teamlc sayxun team vs guliston academy azizbek nuraliyev sanjar rahimjonov t.me/sayxunteamlc +99891 020 03 06 [2,2 ball] 28. ๏ฟฝโƒ—โƒ—๏ฟฝ va ๏ฟฝโƒ—๏ฟฝ oโ€™zaro perpendikulyar birlik vektorlar boโ€™lsa, |5๏ฟฝโƒ—โƒ—๏ฟฝ + 12๏ฟฝโƒ—๏ฟฝ | ning qiymatini toping. a) 7 b) 12 c) 13 d) 17 [2,2 ball] 29. fazodagi ๐‘ƒ nuqtadan tekslikka ikkita ogโ€™ma tushirilgan. ogโ€™malarning uzunliklari 25 va 40 ga teng. oโ€™gmalarning proeksiyalari farqi 25 ga teng boโ€™lsa, ๐‘ƒ nuqtadan tekslikkacha boโ€™lgan masofani toping. a) 20 b) 16 c) 24 d) 18 [2,2 ball] 30. 10 ta odam orasidan 6 tasini shunday tanlash kerakki oldindan belgilangan ikkita odam bir vaqtda tanlanmasin. bunday tanlovlarni necha xil usulda amalga oshirish mumkin? a) 120 b) 140 c) 180 d) 210 [2,2 ball] 31. ๐ด = {๐‘ฅ |๐‘ฅ โˆˆ ๐‘, 30 = ๐‘› โˆ™ ๐‘ฅ; ๐‘› โˆˆ ๐‘ } va ๐ต = {๐‘ฆ |๐‘ฆ โˆˆ ๐‘, 48 = ๐‘ฆ โˆ™ ๐‘›; ๐‘› โˆˆ ๐‘ } ๐ด โˆฉ โ€ฆ
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_________________ [1,7 ball] b) tenglamaning barcha haqiqiy ildizlari yigโ€™indisini toping. javob: b) ________________________________ 37. sin4x = cos4x โˆ’ sin4x tenglama berilgan. [1,5 ball] a) tenglamaning [0;2๐…] oraliqda nechta ildizi bor. javob: a) ________________________________ [1,7 ball] b) tenglamaning [0;2๐…] oraliqdagi eng katta va eng kichik ildizlari ayirmasini toping. javob: b) ________________________________ 38. ๐‘ƒ(2๐‘ฅ โˆ’ 1) = ๐‘ฅ3 โˆ’ 3๐‘ฅ2 + ๐‘ฅ + ๐‘š va ๐‘ƒ(๐‘ฅ) koโ€™phadni ๐‘ฅ โˆ’ 3 ga boโ€™lganda qoldiq 3 boโ€™lsa, [1,5 ball] a) ๐’Ž ning qiymatini toping. javob: a) ________________________________ [1,7 ball] b) ๐‘ท(๐’™ + ๐Ÿ‘) koโ€™phadni ๐’™ + ๐Ÿ‘ ga boโ€™lgandagi qoldiqni toping. javob: b) ________________________________ 39. chizmada ๐ด๐ต๐ถ๐ท va ๐ต๐ธ๐น๐บ kvadrat , โˆ ๐บ๐ป๐ธ = 45ยฐ. agar ๐‘†๐ด๐ต๐ถ๐ท = 3 + 2โˆš2 boโ€™lsa, https://t.me/sayxunteamlc sayxun team vs guliston academy azizbek nuraliyev sanjar rahimjonov t.me/sayxunteamlc +99891 020 03 06 [1,5 ball] a) katta kvadrat tomonini kichik kvadrat tomoniga nisbatini toping. javob: a)___________________________________ [1,7 ball] b) ๐‘ฉ๐‘ฌ๐‘ญ๐‘ฎ kvadrat โ€ฆ

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sayxun team azizbek nuraliyev guliston academy sanjar rahimjonov t/mesayxunteamlc +99891 020 03 06 mock 1 matematika [1,3 ball] 1. ๐‘Ž + ๐‘ + ๐‘ = 25 boโ€™lsa, 50 โˆ’ 2๐‘Ž โˆ’ 2(๐‘ + ๐‘) ning qiymatini toping. a) 2 b) 3 c) 0 d) 1 [2,2 ball] 2. hisoblang: 0,0(6) 0,06 + 0,0(8) 0,08 + 10 9 a) 28 9 b) 10 3 c) 11 3 d) 25 9 [1,3 ball] 3. ๐‘Ž va ๐‘ natural sonlar uchun 2๐‘Ž โˆ™ 3๐‘ = 72 boโ€™lsa, ๐‘Ž + ๐‘ ni qiymatini toping. a) 3 b) 4 c) 5 d) 6 [2,2 ball] 4. yigโ€™ilgan 1 t mevaning 82% i suvdan iborat. maโ€™lum vaqtdan keyin bu mevadagi suvning miqdori 70% ga tushdi. endi โ€ฆ

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